3 Calculate the Esystem values after the addition of 30.00 mL of 0,0500 M HCIO3 to 25,00 mLf0,0400 M NaAuCl₁:3C1O3(aq) + 2AuCl4¯ (aq) + 6OH(aq)3C1O4 (ag) + 2Au(s) +Assume that [KCI] = 0,200 M & [KOH] = 0,100 M throughout the titrationHalf - ReactionEºAu³+ +3e+1,68 V(aq)AuCl(aq)+ 3e+1,00 V+1,19 VCIO4 (aq) + H₂OCu²+2e=Au(s)4+ 4C1 (aq)+2eClO3(aq)2e Cu(s)Au(s)ve and Submit to save and submit. Click Save All Answers to save all answers.+3H₂O+ 3H₂O + 8CI (aq)20H+0.340 V17°C ASave All AnswersSave and Submit11:01□ 6 ENG 2022/05/24

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e the Esystem values after the addition of 30.00 mL of 0,0500 M HCIO3 to 25,00 mL 0 M NaAuCl4: 3(aq) + 2AuCl(aq) +60H* 3C1O4 (ag) (aq) Assume that [KCI] = 0,200 M & [KOH] = 0,100 M throughout the titration Half - Reaction Eº Au³+ +1,68 V (aq) +3e= Au(s) + 2Au(s) + 3H₂O + 8Cr (aq)

e the Esystem values after the addition of 30.00 mL of 0,0500 M HCIO3 to 25,00 mL 0 M NaAuCl4: 3(aq) + 2AuCl(aq) +60H* 3C1O4 (ag) (aq) Assume that [KCI] = 0,200 M & [KOH] = 0,100 M throughout the titration Half - Reaction Eº Au³+ +1,68 V (aq) +3e= Au(s) + 2Au(s) + 3H₂O + 8Cr (aq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Potentiometric Titrations

Potentiometric titration is one of the important titration methods and is mainly carried out to characterize acid solutions. It follows a method similar to that of the normal titration technique, but the main difference is that there is no indicator used in the potentiometric titrations. Instead of using an indicator, electrodes are employed for monitoring the whole titration process. A scientist named Robert Behrend did the potentiometric titration for the first time, and it was done using the mercurous solution and potassium chloride.

Question

Calculate the Esystem values after the addition of 30.00 mL of 0,0500 M HCIO3 to 25,00 mL
f0,0400 M NaAuCl₁:
3C1O3(aq) + 2AuCl4¯ (aq) + 6OH(aq)
3C1O4 (ag) + 2Au(s) +
Assume that [KCI] = 0,200 M & [KOH] = 0,100 M throughout the titration
Half - Reaction
Eº
Au³+ +3e
+1,68 V
(aq)
AuCl(aq)
+ 3e
+1,00 V
+1,19 V
CIO4 (aq) + H₂O
Cu²+2e=
Au(s)
4
+ 4C1 (aq)
+2eClO3(aq)
2e Cu(s)
Au(s)
ve and Submit to save and submit. Click Save All Answers to save all answers.
+
3H₂O
+ 3H₂O + 8CI (aq)
20H
+0.340 V
17°C A
Save All Answers
Save and Submit
11:01
□ 6 ENG 2022/05/24

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