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- Time spent using e-mail per session is normally distributed, with u = 14 minutes and o = 3 minutes. Assume that the time spent per session is normally distributed. Complete parts (a) through (d). a. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 13.8 and 14.2 minutes? 0.259 (Round to three decimal places as needed.) b. If you select a random sample of 25 sessions, what is the probability that the sample mean is between 13.5 and 14 minutes? 0.297 (Round to three decimal places as needed.) c. If you select a random sample of 100 sessions, what is the probability that the sample mean is between 13.8 and 14.2 minutes? 0.497 (Round to three decimal places as needed.) d. Explain the difference in the results of (a) and (c). Choose the correct answer below. The sample size in (c) is greater than the sample size in (a), so the standard error of the mean (or the standard deviation of the sampling distribution) in (c) is V concentrated…The time it takes to complete an online survey is uniformly distributed over the range of 10.1 minutes to 16 minutes. Calculate the probability that it takes a person between 11.2 and 11.9 minutes to complete the survey.The table summarizes results from pedestrian deaths that were caused by automobile accidents. Pedestrian Deaths Driver Pedestrian Intoxicated? Intoxicated? Yes NO. 09 283 Yes 564 NO. If two different pedestrian deaths are randomly selected, find the probability that they both involved pedestrians that were not intoxicated. Report the answer rounded to four decimal place accuracy. Question Help: Written Example Message instructor Submit Question Jump to Answer 43,324 MAR 080 8.
- 2&3Probability Scores 0.05 3 0.1 4 0.25 5 0.05 7 0.4 11 0.15 14 Find the expected value of the above random variable. Next Next QuestionFour coins are tossed, and the number of heads is recorded. Shade the region on the histogram that gives the indicated probability. P(x > 2) Which of the following shaded regions gives the indicated probability? (Type A, B, C, or D.) A) 0.5- 0.38- 0.25- 0.13- 0- 0.5- 0.38 0.25- 0.13- लट 0 1 2 3 4 01 2 3 4 B) D) 0.5- 0.38- 0.25- 0.13- 0- 0.5- 0.38 0.25 0.13- 0- 0 1 2 3 4 0 1 2 3 4
- Find the expected frequency, E,, for the given values of n and p. n= 210, p, = 0.34 %3D (Type an integer or a decimal.) %3DFind the value of X (Left Tailed Probability of 0.5) for v1 = 10 and v2 = 20 degrees of freedom.Probability scores 0.2 2 0.05 7 0.2 8 0.2 13 0.35 14 Find the expected value of the above random variable.
- Practice Exercise Classify the following random variables as discrete or continuous. The number of detective ( facturer Paen ve The weight of nowherne soon in a hospital The number ofe ngs in a family of a region 4. The amount of paint utilized in a building project 5. The number of dropouts in a school district for a period of 10 years 6. The speed of a car 7. The number of female athletes 8. The time needed to finish the test 9. The amount of sugar in a cup of coffee 10. The number of people who are playing LOTTO each dayshaded region on the curve and take a screen and paste it in this problem set document as part of your answer to this question. Use the blank ones in your virtual notebook. (b) When 200 shoppers enter the store, how many shoppers would be expected to be in the store between 22 minutes and 52 minutes? 6.) The mean MCAT total score in a recent year is 500. A random sample of 32 MCAT total scores is selected. What is the probability that the mean score for the sample is (a) less than503, (b) more than 502, and between 498 and 501? Assume σ=10.6. (Source: Association of American Medical Colleges) Hand draw the shaded curves and take a screenshot and attach them as part of the work. 7.) Some college students use credit cards to pay for school-related expenses. For these students,the amount paid is normally distributed, with a mean of $1615 and a standard deviation of $550. (a) What is the probability that a randomly selected college student, who uses a credit card to pay for school-related…Solve for (E)
