e drug 3.6 1.9 2.4 3.7 4.8 4.5 2.9 4.9 4.5 2.3 2.3 3.5 3.6 4.7 3.1 3.2 4.4 5.4 5.4 3.6 6.8 6.6 4.0 4.9 5.6 4.8 drug ach patient by subtracting the number of hours of sleep with the drug from the number without the c Tor a decimal. Round to two decimal places as needed.)
Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 miles away.
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experiments to set up the devices.
![Construct a 90% confidence interval, using the inequality d-t.
To test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night,
researchers randomly select 13 patients and record the number of hours of sleep each gets with and without the new drug.
Patient
Sleep without the drug 3.6 1.9 2.4 3.7 4.8 4.5 2.9 4.9 4.5 2.3 2.3 3.5 3.6
Sleep using the drug
12 3 4 56 7 89 10 11 12 13 D
4.7 3.1 3.2 4.4 5.4 5.4 3.6 6.8 6.6 4.0 4.9 5.6 4.8
Calculate d for each patient by subtracting the number of hours of sleep with the drug from the number without the drug. The confidence interval is <H, <
(Type an integer or a decimal. Round to two decimal places as needed.)
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Let x be the number of hours of sleep with using the drug and y be the number of hours of sleep without using the drug.
Let d be the difference between the number of hours of sleep with using the drug and the number of hours of sleep without using the drug.
Patient | sleep with using drug(x) | sleep without using drug (y) | d=x-y | d-dbar | (d-dbar)^2 |
1 | 4.7 | 3.6 | 1.1 | -0.2538 | 0.064414 |
2 | 3.1 | 1.9 | 1.2 |
-0.1538 |
0.023654 |
3 | 3.2 | 2.4 | 0.8 | -0.5538 | 0.306694 |
4 | 4.4 | 3.7 | 0.7 | -0.6538 | 0.427454 |
5 | 5.4 | 4.8 | 0.6 | -0.7538 | 0.568214 |
6 | 5.4 | 4.5 | 0.9 | -0.4538 | 0.205934 |
7 | 3.6 | 2.9 | 0.7 | -0.6538 | 0.427454 |
8 | 6.8 | 4.9 | 1.9 | 0.5462 | 0.298334 |
9 | 6.6 | 4.5 | 2.1 | 0.7462 | 0.556814 |
10 | 4.0 | 2.3 |
1.7 |
0.3462 | 0.119854 |
11 | 4.9 | 2.3 | 2.6 | 1.2462 | 1.553014 |
12 | 5.6 | 3.5 | 2.1 | 0.7462 | 0.556814 |
13 | 4.8 | 3.6 |
1.2 |
-0.1538 | 0.023654 |
Sum | 17.6 |
5.132308 |
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