E = 12 V C = 150 µF R = 50 R, = 150 R1 E Initially the capacitor is uncharged, and the switch has been for opened for a long time. Then at time t = 0 the switch is closed. After being closed for a long time, the switch is opened. Find the total energy U dissipated in the resistor R2 after the switch is opened. O a. U= 6.08 mJ O b. U = 4.77 mJ O C. U = 10.80 mJ o d. U = 2.34 mJ O e. U= 0.58 mJ

E = 12 V C = 150 µF R = 50 R, = 150 R1 E Initially the capacitor is uncharged, and the switch has been for opened for a long time. Then at time t = 0 the switch is closed. After being closed for a long time, the switch is opened. Find the total energy U dissipated in the resistor R2 after the switch is opened. O a. U= 6.08 mJ O b. U = 4.77 mJ O C. U = 10.80 mJ o d. U = 2.34 mJ O e. U= 0.58 mJ

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Capacitor

The capacitor is an element used to store electrical energy in the electrical field. A capacitor is a form of passive energy.

Question

E = 12 V
C= 150 µF
R = 50
R = 150
E
Initially the capacitor is uncharged, and the switch has been for opened for a long time. Then at time t = 0 the switch is closed.
After being closed for a long time, the switch is opened. Find the total energy U dissipated in the resistor R2 after the switch
is opened.
O a. U= 6.08 mJ
O b. U= 4.77 mJ
O C. U= 10.80 mJ
o d. U= 2.34 mJ
O e. U= 0.58 mJ

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