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E (1) (2) Figure 1 b) Incident and Reflected Waves at a Lossless Dielectric Interface. A plane wave is given as E = E,e-f V/m] and propagates in free space. The wave hits a dielectric wall (e =2e. [F/m]) at normal incidence. With E, 10 V/m, lo4x x 10 H/m, 8.854 x102 F/m, f 1 GHz, calculate: i. The peak electric field intensity, left of the wall. ii. The peak magnetic field intensity, left of the wall.

E (1) (2) Figure 1 b) Incident and Reflected Waves at a Lossless Dielectric Interface. A plane wave is given as E = E,e-f V/m] and propagates in free space. The wave hits a dielectric wall (e =2e. [F/m]) at normal incidence. With E, 10 V/m, lo4x x 10 H/m, 8.854 x102 F/m, f 1 GHz, calculate: i. The peak electric field intensity, left of the wall. ii. The peak magnetic field intensity, left of the wall.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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(1) (2) Figure 1 b) Incident and Reflected Waves at a Lossless Dielectric Interface. A plane wave is given as E = E,e-i#z8 [V/m] and propagates in free space. The wave hits a dielectric wall (8 =2e. [F/m]) at normal incidence. With E, = 10 V/m, lo = 4x x 10" H/m, E, = 8.854 x1012 F/m, f 1 GHz, calculate: i. The peak electric field intensity, left of the wall. ii. The peak magnetic field intensity, left of the wall.
Transcribed Image Text:(1) (2) Figure 1 b) Incident and Reflected Waves at a Lossless Dielectric Interface. A plane wave is given as E = E,e-i#z8 [V/m] and propagates in free space. The wave hits a dielectric wall (8 =2e. [F/m]) at normal incidence. With E, = 10 V/m, lo = 4x x 10" H/m, E, = 8.854 x1012 F/m, f 1 GHz, calculate: i. The peak electric field intensity, left of the wall. ii. The peak magnetic field intensity, left of the wall.
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