Dylan Jones kept careful records of the fuel efficiency of his new car. After the first nine times he filled up the tank, he found the mean was 25.7 miles per gallon (mpg) with a sample standard deviation of 0.9 mpg. (a) Compute the 95 percent confidence interval for his mpg. (Round your answers to 3 decimal places.) (b) How many times should he fill his gas tank to obtain a margin of error below 0.1 mpg? (Round your answer to the nearest whole number. Below are the computations: Below is the computations: Did you see my email with the correct calculations? In your standard deviation of the sample mean you divide by n-1, which is 8. You are dividing by 9. end points of the confidence interval are 20.452 and 22.148 mpg, found by 21.3±2.998(0.8/square root of 8) - This is what my teacher said can you help? The mean was 25.7 miles per gallon (mpg) with a sample standard deviation of 0.9 mpg. xbar = 25.7 s = 0.9 sample size n = 9 c = confidence interval = 95% = 0.95 df = n -1 = 9 - 1 = 8 tα/2, df = t0.025,8 = 2.306 The margin of error E = tα/2, df * s/n⎯⎯√ = 2.306*(0.9/sqrt(9)) = 0.692 a) The 95% confidence interval estimate of the population mean is: xbar- E < μ < xbar + E 25.7 - 0.692 < μ < 25.7 + 0.692 25.008<μ<26.392-This is not the answer! Please stop giving me the same answer. Also,part B is 311 and that is correct. Please HELP.
Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
Dylan Jones kept careful records of the fuel efficiency of his new car. After the first nine times he filled up the tank, he found the
(a) Compute the 95 percent confidence interval for his mpg. (Round your answers to 3 decimal places.)
(b) How many times should he fill his gas tank to obtain a margin of error below 0.1 mpg? (Round your answer to the nearest whole number.
Below are the computations:
Below is the computations:
Did you see my email with the correct calculations? In your standard
deviation of the sample mean you divide by n-1, which is 8. You are
dividing by 9. end points of the confidence interval are 20.452 and 22.148 mpg, found by
21.3±2.998(0.8/square root of 8) - This is what my teacher said can you help?
The mean was 25.7 miles per gallon (mpg) with a sample standard deviation of 0.9 mpg.
xbar = 25.7
s = 0.9
sample size n = 9
c = confidence interval = 95% = 0.95
df = n -1 = 9 - 1 = 8
tα/2, df = t0.025,8 = 2.306
The margin of error E = tα/2, df * s/n⎯⎯√
= 2.306*(0.9/sqrt(9))
= 0.692
a) The 95% confidence
xbar- E < μ < xbar + E
25.7 - 0.692 < μ < 25.7 + 0.692
25.008<μ<26.392-This is not the answer! Please stop giving me the same answer. Also,part B is 311 and that is correct. Please HELP.
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