dy For the differential equation = (y - 3) (+2) there is equilibrium solutions. The positive equilibrium solution is [Select] The negative equilibrium solution is [Select] +-3, +-4 V , which is [Select] which is [Select] stable/unsta ble Hint: to find if the equilibrium solution stable or unstable, you may want to draw the slope field using online graphing Cools)
dy For the differential equation = (y - 3) (+2) there is equilibrium solutions. The positive equilibrium solution is [Select] The negative equilibrium solution is [Select] +-3, +-4 V , which is [Select] which is [Select] stable/unsta ble Hint: to find if the equilibrium solution stable or unstable, you may want to draw the slope field using online graphing Cools)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Please explain the answer and the process calculating equilibrium. Thank you!
![dy
dx
= (y − 3) (½ + 2) there is equilibrium solutions.
For the differential equation =
The positive equilibrium solution is
[Select]
The negative equilibrium solution is [Select]
+-3, +-4
which is [Select]
which is [Select]
stable/unsta
ble
(Hint: to find if the equilibrium solution stable or unstable, you may want to draw the slope field using online graphing
tools)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff4893c46-a94c-4c81-a9fc-277ce07300a6%2F9a2034dc-93d4-433a-9eab-6e2520202fbc%2F5xzkkrb_processed.png&w=3840&q=75)
Transcribed Image Text:dy
dx
= (y − 3) (½ + 2) there is equilibrium solutions.
For the differential equation =
The positive equilibrium solution is
[Select]
The negative equilibrium solution is [Select]
+-3, +-4
which is [Select]
which is [Select]
stable/unsta
ble
(Hint: to find if the equilibrium solution stable or unstable, you may want to draw the slope field using online graphing
tools)
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