dy dy dt * dx dt dx Ex3: Use the chain rule to express: in terz dx dy t2 a) y = and t = v2x +1 %3D %3D t2+1 1 b) y = 241 and x = V4t + 1 c) y = ( 1 x 3D t2 and -1 at t = 2 %3D t+1. 1 d) y = 1- 1 and t = 1-x at x = 2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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dy dy dt
dx
dt dx
dy
Ex3: Use the chain rule to express-
in tern
dx
t2
a) y =
and t = v2x + 1
%3D
t2+1
1
b) y =
and x = V4t +1
t2+1
c) y = (
1
and x =
1
at t = 2
t+1,
t2
d) y = 1– 1
and t =
1-x
at x = 2
Sol:
t2
a) y :
2t(t2+1)-2t.t2
dy
2t
%3D
%3D
%3D
t2+1
dt
(t2+1)2
(t2+1)2
=!:(2x + 1) 2 = Ei
1
dt
t = (2x + 1)2 =
dx
1
%3D
%3D
2
V2x+1
dy
dy
%3D
dt
2/2x+1
2t
1
%3D
%3D
dx
(2x+1)+1) VZ=
dt
dx
(t2+1)2 V2x+1
b) y = (t2 + 1)-1=
dy
2t
-2t(t2 + 1)-2
dt
(t2+1)2
Transcribed Image Text:dy dy dt dx dt dx dy Ex3: Use the chain rule to express- in tern dx t2 a) y = and t = v2x + 1 %3D t2+1 1 b) y = and x = V4t +1 t2+1 c) y = ( 1 and x = 1 at t = 2 t+1, t2 d) y = 1– 1 and t = 1-x at x = 2 Sol: t2 a) y : 2t(t2+1)-2t.t2 dy 2t %3D %3D %3D t2+1 dt (t2+1)2 (t2+1)2 =!:(2x + 1) 2 = Ei 1 dt t = (2x + 1)2 = dx 1 %3D %3D 2 V2x+1 dy dy %3D dt 2/2x+1 2t 1 %3D %3D dx (2x+1)+1) VZ= dt dx (t2+1)2 V2x+1 b) y = (t2 + 1)-1= dy 2t -2t(t2 + 1)-2 dt (t2+1)2
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