d³y dt3 dy + 4 dt2 + 5 dt + 2y = 10 cost y(0) = 0, y'(0) = 0, y"(0) = 0 %3D

Q: 4 ( Calculate -2x dy

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Q: y" + y = sin x %3D

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Q: y"+y' - 2y = x2

A: Solution :-

Q: 4/3 5² = 2² -3 (2²) *² y' x

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Q: Find y': y=- Vx* + 4

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Q: Dy/dy=x^2-y^2/2xy.     Y(1)=0

A: Given that: dydx=x2-y22xy and y(1)=0

Q: yy' = x(y)² + 4

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Q: y y' + (2х + 3у) = 0 y(x) = ? =>

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Q: Solve the equation ny separations of the variables: y' - xy^3 = 0

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Q: Find general soulution (x+1)dy/dx +(x+2)y=6xe^-x

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Q: dy/dx and d^2y/dx^2

A: Here; x=e-7t+2 .................. .......(1) y=6e2t+e-3t-4t   ......................(2)

Q: Sve SVé -3 dt u = Ve' – 3

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Q: a) Find the particular antiderivative that satisfies the following conditions:…

A: dxdt=8et-3x0=5

Q: y' = vsinx y +1

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Q: dy/dx (y=x^2(4x+1)^3)

A: To find dy/dx we differenciate both sides with respect to x.On the right side use the Product…

Q: y' =xy

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Q: If the solution of y' = 2(2x - y) passes through the point (0,1), determine x when y = 7.

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Q: Solve Xy"-xy' +y = a+3ln(x), y)=Q , yl)=1 %3D

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Q: ln p= a + b/t + cln(t) + dt^2 Is this equation linear or non linear

A: To determine whether the below equation is linear or non linear. lnp=a+bt+clnt+dt2

Q: Find dz/dx for the equitation xe^z +ze^y= x+y

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Q: y" +4y=28 (1/4), y(0) = 0, y'(0) = 0

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Q: 13. Equation from Exercise 1; y(0) = 1, y(-2) = -1, y(0) = 3, y(0) = 2. %3D

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Q: y-5y't 4y =O x10)-5 y'l0)=2

A: We have to find the particular solution of the initial value problem…

Q: 2хуу' — 1 + у? y = 2; x = 1 %3D %3D

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Q: e^x + y)dx +(2 + X + ye^y)dy= 0 ,y(0)=1

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Q: Solve y'"+ 5y' + 4y = 0, y(0) = - 8, y'(0) = 17 y(t) = %3D

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Q: 5-(x^2-y^4)dy/dx=xy

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Q: Find dx/dt, dy/dt, dy/dx for  x=9t-9ln(t), y=6t^2-6t^-2

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Q: x² + 3x + 2 y' = y(1) = 4 у — 2

A: y'=x2+3x+y-2 ; y(1)=4

Q: x² +2 .3 x' +6x

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Q: Find the general solution to this exact equation: y + (2ty-e^(-2y) ) dy/dt = 0

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Q: (y+1)^3 dx + (y+1)e^-x dy=0

A: (y+1)^3 dx + (y+1)e^-x dy=0

Q: 6. y = V7+ V3x+1 4х-5 y 2x+1 7. у 3 8. у %3 Зx+1 y = Зx? +2

A: according to our guidelines we can answer only one question and rest can be reposted.thanku

Q: y' = e2x + y – 1 %3D

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Q: solve for      xydy + 2(x^2 +2y^2)dy = 0 when x=0 and y=1

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Q: Solve x’y dx = (x'+y°)dy X +

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