dv (№0-0-7)2 2(1+0.01) (~1010-1) (11010+1) 18-6 Ар " 18.6

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I just had a question on the step that I marked blue, how did they get the number (2) please explain in details

ja-jo
dt =
=
dt =
dt =
ข
dv
9.81 [1-v² (10-)] m/s²
dv
9.81 [1-(0.01)³]
dv
dv
['dt = ["d
dv
=
a
Put the value of a
9-311-121011]
dv
9.811
dv
dt
9.81
2 (1+0.01v)
2 (1-0.01v)
9.31 [1-(16)7]
1+0.01
t=
50 In
9.81
1-0.01
9.81t 50 In
1+0.01
(2).
1-0.01
?
9.81
dv
9.31 [1-(0.011)]
9-81
dv
(1+0.01) (1-0.010)
Assume, Ito.olv = p
=> dv= 100p
dv
2 (1+0.01)
100 dp
2 P
= 504yp
= (506 (1+0.01)
Similarly
dv
=
== Soby (1-0.01v))
9.81
_
dv
2(1+0.01)
+
dv
2(L-ཋ.»ry〕
+༢(ད- ༠-༠)
11/17 (50l02 (1+0.011) - Soly (1-0.01)
9.81
1(H.
-
-0.01V
t = 11311 [50 42
9.81
9.81+=
1-0.01v
1+0.01v
Transcribed Image Text:ja-jo dt = = dt = dt = ข dv 9.81 [1-v² (10-)] m/s² dv 9.81 [1-(0.01)³] dv dv ['dt = ["d dv = a Put the value of a 9-311-121011] dv 9.811 dv dt 9.81 2 (1+0.01v) 2 (1-0.01v) 9.31 [1-(16)7] 1+0.01 t= 50 In 9.81 1-0.01 9.81t 50 In 1+0.01 (2). 1-0.01 ? 9.81 dv 9.31 [1-(0.011)] 9-81 dv (1+0.01) (1-0.010) Assume, Ito.olv = p => dv= 100p dv 2 (1+0.01) 100 dp 2 P = 504yp = (506 (1+0.01) Similarly dv = == Soby (1-0.01v)) 9.81 _ dv 2(1+0.01) + dv 2(L-ཋ.»ry〕 +༢(ད- ༠-༠) 11/17 (50l02 (1+0.011) - Soly (1-0.01) 9.81 1(H. - -0.01V t = 11311 [50 42 9.81 9.81+= 1-0.01v 1+0.01v
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