During the titration of an HClO4solution with 0.10320M NaOH, a CHEM 3A student,Juan becamedistracted and overshot the endpoint. A fellow student Pedrosuggested that he should record the present volume of NaOH added and titrate the excess with a standard acid solution. If the original sample volume was 25.000mL, the volume of NaOH added was 28.060mL. It took 3.4700 mL of 0.10940 M HCl to back-titrate the NaOH andcalculate the molar concentration of the original HClO4solution.

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A: The Kb of methylamine is given to be 3.7×10-4. Its pKb can be calculated as: pKb=-logKb…

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A: Given:   Trial-1 Trial-2 Molarity of HCl 31.34 31.44

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Q: 4

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Q: Calculate the pH

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A: It is an acid – base titration. The complete neutralization reaction is given below.

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.