During a reversible process, 396 kJ of heat is added to 1.264 kg of a certain gas while the volume is held constant. For this gas, Cp 2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The initial temperature is 26.7°C and the initial pressure is 586 kPa. Determine the following: (1) The universal gas rate constant for the gas is we relate the two heat capacity values?) KJ/(kg-K) (Hint: How do m3 (Hint: If the ideal gas equation is expressed in (2) The volume, V = terms of mass, it becomes PV=mRT) (3) The final pressure, P2 = kPa (4) The final temperature, T2 = °C (5) W = kJ (6) Q = kJ %3D (7) DU = kJ (8) DH = kJ
During a reversible process, 396 kJ of heat is added to 1.264 kg of a certain gas while the volume is held constant. For this gas, Cp 2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The initial temperature is 26.7°C and the initial pressure is 586 kPa. Determine the following: (1) The universal gas rate constant for the gas is we relate the two heat capacity values?) KJ/(kg-K) (Hint: How do m3 (Hint: If the ideal gas equation is expressed in (2) The volume, V = terms of mass, it becomes PV=mRT) (3) The final pressure, P2 = kPa (4) The final temperature, T2 = °C (5) W = kJ (6) Q = kJ %3D (7) DU = kJ (8) DH = kJ
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:During a reversible process, 396 kJ of heat is added to 1.264 kg of a certain gas while the
volume is held constant. For this gas, Cp =2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The
initial temperature is 26.7°C and the initial pressure is 586 kPa. Determine the following:
(1) The universal gas rate constant for the gas is
we relate the two heat capacity values?)
kJ/(kg-K) (Hint: How do
m3
(Hint: If the ideal gas equation is expressed in
(2) The volume, V =
terms of mass, it becomes PV=mRT)
(3) The final pressure, P2 =
kPa
(4) The final temperature, T2 =
°C
(5) W =
kJ
(6) Q =
kJ
(7) DU =
kJ
%3D
(8) DH =
kJ
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