During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 144 g baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 11.7 m/s, shatters the glass as it passes through, and leaves the window at 8.21 m/s with no change of direction. Calculate the magnitude of the impulse J that the glass imparts to the baseball. If the baseball is in contact with the glass for a time At of 10.1 ms, what is the magnitude of the average force Faverage of the glass on the ball? J = Faverage || N.S N

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**Physics Problem: Impulse and Average Force**

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 144 g baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 11.7 m/s, shatters the glass as it passes through, and leaves the window at 8.21 m/s with no change of direction.

**Question 1:**
Calculate the magnitude of the impulse \( J \) that the glass imparts to the baseball.

\[ J = \] [__________] N·s

**Question 2:**
If the baseball is in contact with the glass for a time \( \Delta t \) of 10.1 ms, what is the magnitude of the average force \( F_{\text{average}} \) of the glass on the ball?

\[ F_{\text{average}} = \] [__________] N

---

**Instructions:**

1. **Impulse Calculation:**
   - Use the impulse-momentum theorem to calculate \( J \).
   - Consider the changes in momentum as the ball passes through the glass.

2. **Average Force Calculation:**
   - Convert the contact time from milliseconds to seconds.
   - Use the formula \( F_{\text{average}} = \frac{J}{\Delta t} \).

Ensure all units are consistent, and provide your answers with appropriate significant figures.
Transcribed Image Text:**Physics Problem: Impulse and Average Force** During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 144 g baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 11.7 m/s, shatters the glass as it passes through, and leaves the window at 8.21 m/s with no change of direction. **Question 1:** Calculate the magnitude of the impulse \( J \) that the glass imparts to the baseball. \[ J = \] [__________] N·s **Question 2:** If the baseball is in contact with the glass for a time \( \Delta t \) of 10.1 ms, what is the magnitude of the average force \( F_{\text{average}} \) of the glass on the ball? \[ F_{\text{average}} = \] [__________] N --- **Instructions:** 1. **Impulse Calculation:** - Use the impulse-momentum theorem to calculate \( J \). - Consider the changes in momentum as the ball passes through the glass. 2. **Average Force Calculation:** - Convert the contact time from milliseconds to seconds. - Use the formula \( F_{\text{average}} = \frac{J}{\Delta t} \). Ensure all units are consistent, and provide your answers with appropriate significant figures.
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