### Question 9 of 22---**Problem Statement:**During a lightning storm, a lightning bolt causes 100 C of charge to move through a potential difference of \(5 \times 10^5\) V. If the power associated with the lightning strike is \(4 \times 10^8\) W, how long did the strike last?**Options:**- ( ) 0.350 s- ( ) 0.125 s- ( ) 100 s- ( ) 0.023 s- ( ) None of the above### Explanation:To determine how long the lightning strike lasted, we need to use the equation relating power (P), voltage (V), charge (Q), and time (t). The equation is derived from the relationship:\[ P = \frac{V \times Q}{t} \]Rearranging the formula to solve for time (t), we get:\[ t = \frac{V \times Q}{P} \]Substitute the given values into the equation:\[ V = 5 \times 10^5 \, \text{V} \]\[ Q = 100 \, \text{C} \]\[ P = 4 \times 10^8 \, \text{W} \]So,\[ t = \frac{5 \times 10^5 \, \text{V} \times 100 \, \text{C}}{4 \times 10^8 \, \text{W}} \]\[ t = \frac{5 \times 10^7}{4 \times 10^8} \]\[ t = 0.125 \, \text{s} \]Therefore, the correct answer is:- (•) 0.125 s

Given data: Charge (Q) = 100 C Potential difference (V) = 5×105 V Power (P) = 4×108 W Required:…

During a lightning storm, a lighting bolt causes 100 C of charge to move through a potential difference of 5 x 105 V. If the power associated with the lightening strike is 4 x 108 W, how long did the strike last? 0.350 s 0.125 s 100 s 0.023 S None of the above

During a lightning storm, a lighting bolt causes 100 C of charge to move through a potential difference of 5 x 105 V. If the power associated with the lightening strike is 4 x 108 W, how long did the strike last? 0.350 s 0.125 s 100 s 0.023 S None of the above

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Electric Potential

Section: Chapter Questions

Problem 25.3CQ: When charged particles are separated by an infinite distance, the electric potential energy of the...

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