Dumb question, just starting to learn about mass spectometry. I know we have to memorize the common radical fragments, M-15, M-29, etc, but lloking at the example, those numbers dont crrespond to the absorbance or the m/z, so for example, M-29.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Dumb question, just starting to learn about mass spectometry. I know we have to memorize the common radical fragments, M-15, M-29, etc, but lloking at the example, those numbers dont crrespond to the absorbance or the m/z, so for example, M-29. The absorbance for M-29 is at 100 , while the m/z is at 43. How is it designated to be M-29?

Relative Abundance
100
80
60
40-
20-
of
10
-(M-57)
20
30
-(M-43)
40
-(M-29)
m/z
50
-(M-15)
60
(M)**.
70
80
Relative Intensity
100 T
80-
60
40
20-
0+
Transcribed Image Text:Relative Abundance 100 80 60 40- 20- of 10 -(M-57) 20 30 -(M-43) 40 -(M-29) m/z 50 -(M-15) 60 (M)**. 70 80 Relative Intensity 100 T 80- 60 40 20- 0+
Expert Solution
Step 1

molar mass is 72

molecular ion have (M+.) = m/z = 72

(M-15) = m / z = (72 - 15) = 57

so (M-15)  means m/z = 57 fragment.

(M-29) means  m / z = 43 fragment.

and

(M-43) means m/z = 29 fragment.

and

(M-57) means m/z = 15 fragment.  

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