Let me tell you about their task:The students were provided with 5 drinks (sports/soft drinks) and they were asked to determine the glucose concentration in these drinks in the units of g/100mL. (Why these units? Well, once the students have the concentrations in g/100mL they will be able to compare their values with the nutritional values given on the drink bottles’ labels).The samples of the five drinks were all diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for the students is that the dilution factor will have to be taken into consideration in their calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink).The students decided to save time and form five groups where each group was responsible for analysing the concentration of one of the drinks.Each group measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar).Drink #Glucose Concentration in mM12.455 mM20.307 mM33.750 mM41.100 mM51.500 mM From here, each group needs to convert the concentration of their drink from mM of the diluted drink into g/100mL of the undiluted drink. This is where you come in! The students are stuck at this point and really need your help! Main Goal: Convert the experimental glucose concentration (provided in the table below) from mM (millimolar) to g/100 mL. Hints & TipsTake the 1/100 dilution factor into considerationMolarity will open the doors for you to get to grams.Once at M assume 1L of solution. (Hint: this will help you when converting from M to moles)You will also need to calculate the molar mass of glucose which has the formula C6H12O6There are 5 steps in total Task 1: Write a step-by-step guide with key words for the Chem 2 students on how to do these calculations. You can use diagrams, a table or just type the steps out. Ensure the steps are clearly written and easy to follow.

Answered: Drink # Glucose Concentration in mM 1…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Let me tell you about their task:

The students were provided with 5 drinks (sports/soft drinks) and they were asked to determine the glucose concentration in these drinks in the units of g/100mL. (Why these units? Well, once the students have the concentrations in g/100mL they will be able to compare their values with the nutritional values given on the drink bottles’ labels).
The samples of the five drinks were all diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for the students is that the dilution factor will have to be taken into consideration in their calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink).
The students decided to save time and form five groups where each group was responsible for analysing the concentration of one of the drinks.
Each group measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar).

Drink #	Glucose Concentration in mM
1	2.455 mM
2	0.307 mM
3	3.750 mM
4	1.100 mM
5	1.500 mM

From here, each group needs to convert the concentration of their drink from mM of the diluted drink into g/100mL of the undiluted drink. This is where you come in! The students are stuck at this point and really need your help!

Main Goal: Convert the experimental glucose concentration (provided in the table below) from mM (millimolar) to g/100 mL.

Hints & Tips

Take the 1/100 dilution factor into consideration
Molarity will open the doors for you to get to grams.
Once at M assume 1L of solution. (Hint: this will help you when converting from M to moles)
You will also need to calculate the molar mass of glucose which has the formula C₆H₁₂O₆
There are 5 steps in total

Task 1: Write a step-by-step guide with key words for the Chem 2 students on how to do these calculations. You can use diagrams, a table or just type the steps out. Ensure the steps are clearly written and easy to follow.

Expert Solution

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We know, concentration of a solution is defined as the amount of solute dissolved per unit solvent.

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