Draw the two possible products produced in this E1 elimination. Ignore any inorganic byproducts.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**E1 Elimination Reaction Products**

In this E1 elimination reaction, we start with a chlorinated hydrocarbon. The task is to predict the two possible organic products, ignoring any inorganic byproducts. 

**Structural Description:**
1. The starting molecule is a chlorinated compound with the chlorine (Cl) atom attached to a carbon that is connected to two other carbon atoms. This setup suggests that the molecule will undergo an E1 elimination mechanism.

**Reaction Conditions:**
- Solvent: Water (H₂O)
- Conditions: Heat

**Expected Products:**
The reaction involves the elimination of the chlorine atom and the formation of a double bond (C=C) in its place. Two possible alkenes can form based on the different positions where the double bond may arise:

1. **Product 1:** The double bond forms between the carbon atom that loses the chlorine and one of its adjacent carbons.
   
2. **Product 2:** The double bond forms between the carbon atom that loses the chlorine and the other adjacent carbon.

Since E1 mechanisms typically involve the formation of a carbocation intermediate, the stability of these intermediates will influence the major product. In many cases, the more substituted alkene (more stable) will be the major product due to Zaitsev's rule.

This exercise emphasizes predicting reaction outcomes and illustrates the concept of regioselectivity in organic reactions.
Transcribed Image Text:**E1 Elimination Reaction Products** In this E1 elimination reaction, we start with a chlorinated hydrocarbon. The task is to predict the two possible organic products, ignoring any inorganic byproducts. **Structural Description:** 1. The starting molecule is a chlorinated compound with the chlorine (Cl) atom attached to a carbon that is connected to two other carbon atoms. This setup suggests that the molecule will undergo an E1 elimination mechanism. **Reaction Conditions:** - Solvent: Water (H₂O) - Conditions: Heat **Expected Products:** The reaction involves the elimination of the chlorine atom and the formation of a double bond (C=C) in its place. Two possible alkenes can form based on the different positions where the double bond may arise: 1. **Product 1:** The double bond forms between the carbon atom that loses the chlorine and one of its adjacent carbons. 2. **Product 2:** The double bond forms between the carbon atom that loses the chlorine and the other adjacent carbon. Since E1 mechanisms typically involve the formation of a carbocation intermediate, the stability of these intermediates will influence the major product. In many cases, the more substituted alkene (more stable) will be the major product due to Zaitsev's rule. This exercise emphasizes predicting reaction outcomes and illustrates the concept of regioselectivity in organic reactions.
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