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Draw the stepwise, arrow-pushing mechanism for the following reaction. Show each step with arrows indicating eleectron movement.

Draw the stepwise, arrow-pushing mechanism for the following reaction. Show each step with arrows indicating eleectron movement.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw the stepwise, arrow-pushing mechanism for the following reaction. Show each step with arrows indicating eleectron movement.

This diagram illustrates a chemical reaction involving the conversion of a bromocyclohexane compound to an ethoxycyclohexane compound in the presence of ethanol. **Reactant:** - The structure on the left is a cyclohexane ring with a bromine atom (Br) attached, represented as "Br" with a solid wedge, indicating its position above the plane of the ring. - A hydrogen atom (H) is also shown with a dashed wedge, indicating its position below the plane of the ring. **Reagent:** - Ethanol (CH₃CH₂OH) is used as a reagent, shown above the reaction arrow. **Product:** - The resulting structure on the right is a cyclohexane ring with an ethoxy group (OCH₂CH₃) replacing the bromine atom. This group is depicted with a solid wedge to show its orientation above the plane of the ring. - A hydrogen atom (H) is indicated with a dashed wedge, maintaining its below-plane orientation. - The product is shown with "+ enantiomer," indicating that an enantiomeric (mirror image) version of the product is also formed in the reaction. This reaction involves a nucleophilic substitution where the bromine is replaced by the ethoxy group from ethanol, resulting in two enantiomers of ethoxycyclohexane.
Transcribed Image Text:This diagram illustrates a chemical reaction involving the conversion of a bromocyclohexane compound to an ethoxycyclohexane compound in the presence of ethanol. **Reactant:** - The structure on the left is a cyclohexane ring with a bromine atom (Br) attached, represented as "Br" with a solid wedge, indicating its position above the plane of the ring. - A hydrogen atom (H) is also shown with a dashed wedge, indicating its position below the plane of the ring. **Reagent:** - Ethanol (CH₃CH₂OH) is used as a reagent, shown above the reaction arrow. **Product:** - The resulting structure on the right is a cyclohexane ring with an ethoxy group (OCH₂CH₃) replacing the bromine atom. This group is depicted with a solid wedge to show its orientation above the plane of the ring. - A hydrogen atom (H) is indicated with a dashed wedge, maintaining its below-plane orientation. - The product is shown with "+ enantiomer," indicating that an enantiomeric (mirror image) version of the product is also formed in the reaction. This reaction involves a nucleophilic substitution where the bromine is replaced by the ethoxy group from ethanol, resulting in two enantiomers of ethoxycyclohexane.
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