Draw the starting alkyne that would lead to this major product under these conditions.

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### Question 27 of 32

**Prompt:**
Draw the starting alkyne that would lead to this major product under these conditions.

**Diagram Explanation:**

1. **Starting Compound:**
   - The top section contains a structural formula within a dashed box labeled "Select to Edit," representing the alkyne reactant. The alkyne structure consists of a carbon chain with a triple bond and two additional groups: a methyl group (CH₃) branching on the second carbon from the left and two methyl groups (CH₃) bonded to the same carbon next to the triple bond.

2. **Reaction Condition:**
   - An arrow points downward, indicating the reaction pathway. The condition labeled alongside the arrow is "HBr (1 equiv)," specifying that the reaction involves one equivalent of hydrogen bromide.

3. **Major Product:**
   - The bottom section shows the resulting structure of the major product. The triple bond has reacted to form a double bond, and a bromine atom (Br) is attached to one of the carbons where the triple bond was previously located, forming a vinyl bromide configuration.

This diagram and description represent a typical hydrohalogenation reaction where an alkyne reacts with HBr to form a vinyl bromide product.
Transcribed Image Text:### Question 27 of 32 **Prompt:** Draw the starting alkyne that would lead to this major product under these conditions. **Diagram Explanation:** 1. **Starting Compound:** - The top section contains a structural formula within a dashed box labeled "Select to Edit," representing the alkyne reactant. The alkyne structure consists of a carbon chain with a triple bond and two additional groups: a methyl group (CH₃) branching on the second carbon from the left and two methyl groups (CH₃) bonded to the same carbon next to the triple bond. 2. **Reaction Condition:** - An arrow points downward, indicating the reaction pathway. The condition labeled alongside the arrow is "HBr (1 equiv)," specifying that the reaction involves one equivalent of hydrogen bromide. 3. **Major Product:** - The bottom section shows the resulting structure of the major product. The triple bond has reacted to form a double bond, and a bromine atom (Br) is attached to one of the carbons where the triple bond was previously located, forming a vinyl bromide configuration. This diagram and description represent a typical hydrohalogenation reaction where an alkyne reacts with HBr to form a vinyl bromide product.
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