Draw the starting alkyne that would lead to the following two products under these conditions. Select to Draw 1. KMNO4, OH- (warm) 2. НзО* HO. Но

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**Title: Organic Chemistry Reaction: Identifying Alkynes**

**Objective:**

Draw the starting alkyne that would lead to the following two products under these specified reaction conditions.

---

**Instructions:**

1. **Reaction Conditions:**

   - Use the following reagents in the reaction:
     1. **KMnO₄, OH⁻** (warm conditions)
     2. **H₃O⁺**

2. **Expected Chemical Transformation:**

   - The reaction involves oxidation of an alkyne to yield two carboxylic acid products.

3. **Chemical Products Formed:**

   - The products of the reaction are two carboxylic acids. The structure of the products is shown in the diagram:
     - **Product 1:** A six-membered cyclic compound with a carboxylic acid (–COOH) and an alcohol (–OH) group attached to adjacent carbons.
     - **Product 2:** A linear chain with a carboxylic acid group (–COOH) and a methyl group (–CH₃).

4. **Challenge:**

   - Draw the structure of the alkyne that would react under these conditions to yield the mentioned products. Use the "Select to Draw" tool to illustrate.

5. **Diagram Description:**

   - The illustration involves a process flow where an unspecified alkyne (to be drawn) undergoes reaction steps, leading finally to the depicted carboxylic acid structures.

**Discussion:**

Understanding this reaction requires knowledge of alkyne oxidation, specifically through oxidative cleavage where KMnO₄ is used to break triple bonds and form carboxylic acids. This understanding will aid in hypothesizing the original alkyne structure needed to obtain the desired products.

Remember, mastering these transformations is crucial for organic synthesis and reaction mechanism analysis in advanced chemistry studies!
Transcribed Image Text:**Title: Organic Chemistry Reaction: Identifying Alkynes** **Objective:** Draw the starting alkyne that would lead to the following two products under these specified reaction conditions. --- **Instructions:** 1. **Reaction Conditions:** - Use the following reagents in the reaction: 1. **KMnO₄, OH⁻** (warm conditions) 2. **H₃O⁺** 2. **Expected Chemical Transformation:** - The reaction involves oxidation of an alkyne to yield two carboxylic acid products. 3. **Chemical Products Formed:** - The products of the reaction are two carboxylic acids. The structure of the products is shown in the diagram: - **Product 1:** A six-membered cyclic compound with a carboxylic acid (–COOH) and an alcohol (–OH) group attached to adjacent carbons. - **Product 2:** A linear chain with a carboxylic acid group (–COOH) and a methyl group (–CH₃). 4. **Challenge:** - Draw the structure of the alkyne that would react under these conditions to yield the mentioned products. Use the "Select to Draw" tool to illustrate. 5. **Diagram Description:** - The illustration involves a process flow where an unspecified alkyne (to be drawn) undergoes reaction steps, leading finally to the depicted carboxylic acid structures. **Discussion:** Understanding this reaction requires knowledge of alkyne oxidation, specifically through oxidative cleavage where KMnO₄ is used to break triple bonds and form carboxylic acids. This understanding will aid in hypothesizing the original alkyne structure needed to obtain the desired products. Remember, mastering these transformations is crucial for organic synthesis and reaction mechanism analysis in advanced chemistry studies!
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