**Instructions for Drawing:****Title:** Drawing the Skeletal Structure of (S)-3-chloro-2-phenylpropanoic Acid**Task:** Draw the skeletal (line-bond) structure for (S)-3-chloro-2-phenylpropanoic acid. Use a dash or wedge bond to indicate stereochemistry of substituents on asymmetric centers, where applicable.**Diagram Area:**- A dashed box labeled "Select to Draw"**Details for Drawing:**- Ensure accurate representation of chemical bonds and structures.- Highlight stereochemistry using dashed or wedged bonds at asymmetric centers.- The skeletal structure should clearly represent the molecular framework of (S)-3-chloro-2-phenylpropanoic acid. This exercise reinforces understanding of organic chemistry nomenclature, stereochemistry, and molecular drawing conventions. **Instruction:**Draw the product of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry where appropriate. Ignore inorganic byproducts.**Structure Description:**- **Reactant**: The structure is a naphthalene system with an ethyl group attached to the carbon at the end. **Reaction Conditions:**- **Reagent**: Sodium dichromate (Na₂Cr₂O₇)- **Solvent**: Water (H₂O) and acetic acid (CH₃CO₂H)**Task:**- A box is indicated with dashed lines labeled "Select to Draw" for the user to draw the reaction product.

Since you have asked multiple question, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question. Please find your solution below : To assign the configuration, first we need to give the priority to the groups. The atom with higher atomic number has the higher priority. When there is a tie in the atomic number then relative priority is assigned by proceeding to the next atom along the change until the first difference is observed. In this molecule, -COOH is given the first priority, -CH2Cl is given second, phenyl group is given third and -H is given the fourth priority. For giving the S configuration, place the groups accordingly to their priorities in counterclockwise direction. Highest priority group is placed on wedge bond and least priority group on dashed bond. Rest groups are attached through normal line bonds.Therefore, the structure is :Hope this will help you. Thank you :)