Draw the product formed when the compound shown below undergoes a reaction with Br2 in CH2Cl2. Interactive 3D display mode `CH3

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Draw the product formed when the compound shown below undergoes a

reaction with Br2 in CH2Cl2.

 

**Title: Reaction of Cyclohexene with Bromine in Dichloromethane**

**Instruction:**
Draw the product formed when the compound shown below undergoes a reaction with Br₂ in CH₂Cl₂.

**Molecular Structure:**

- **Structure:** Cyclohexene with an ethyl group attached to the double bond, represented as a hexagonal ring with one double bond and an ethyl group (CH₂CH₃) attached to one of the double-bonded carbons.

**Interactive Element:**
- **Interactive 3D display mode**: This feature allows users to visualize the molecular structure in three dimensions to better understand the compound’s geometry and the reaction pathway.

**Explanation:**
In this reaction, the compound undergoes an electrophilic addition reaction with bromine, where the Br₂ molecule adds across the double bond of cyclohexene. The resulting product will have bromine atoms added to the carbons that originally participated in the double bond, converting it to a single bond and forming a dibromo derivative.
Transcribed Image Text:**Title: Reaction of Cyclohexene with Bromine in Dichloromethane** **Instruction:** Draw the product formed when the compound shown below undergoes a reaction with Br₂ in CH₂Cl₂. **Molecular Structure:** - **Structure:** Cyclohexene with an ethyl group attached to the double bond, represented as a hexagonal ring with one double bond and an ethyl group (CH₂CH₃) attached to one of the double-bonded carbons. **Interactive Element:** - **Interactive 3D display mode**: This feature allows users to visualize the molecular structure in three dimensions to better understand the compound’s geometry and the reaction pathway. **Explanation:** In this reaction, the compound undergoes an electrophilic addition reaction with bromine, where the Br₂ molecule adds across the double bond of cyclohexene. The resulting product will have bromine atoms added to the carbons that originally participated in the double bond, converting it to a single bond and forming a dibromo derivative.
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