Draw the most stable product formed in each of the reactions shown. Reaction (a) 2 مهر NaOEt, EtOH A Draw the product of reaction (a). Select Draw / |||||| Rings C H O More

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Chapter1: Chemical Foundations
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### Reaction Mechanism Explanation

**Objective:**  
Draw the most stable product formed in the given reaction.

**Reaction (a):**  
- **Starting Material:** A six-membered cyclic ester (lactone) with a propyl substituent.
- **Reagents:** Sodium ethoxide (NaOEt) in ethanol (EtOH) and heat (Δ).

**Reaction Details:**  
- The reaction involves the use of a strong base, NaOEt, in an alcoholic solvent, EtOH, often leading to an elimination or substitution process.
- Heat is provided, indicating that the reaction might involve elimination, likely leading to the formation of an alkene.

**Task:**  
- Using the drawing tools in the interface (lines for single bonds, double bonds, and rings), determine the most stable alkene product formed after the elimination reaction.
- The reaction should be considered under thermodynamic control due to the presence of heat, suggesting the most substituted alkene is the favored product.

### Drawing Interface Explanation

**Tools Available:**

- **Select**: Choose this tool to highlight and manipulate parts of the structure.
- **Draw**: Use this tool to add bonds:
  - **Single Bond (/)**
  - **Double Bond (=)**
  - **Triple Bond (≡)**
- **Rings**: Utilize pre-defined rings for adding structures like cyclohexane or benzene.
- **Atoms**: Click on “C”, “H”, or “O” to add carbon, hydrogen, or oxygen atoms specifically.

Use these tools to depict the structure of the most stable product obtained from Reaction (a). Focus on forming a thermodynamically stable alkene with the base-induced elimination of a proton, resulting in a double bond within the ring or between ring substituents.
Transcribed Image Text:### Reaction Mechanism Explanation **Objective:** Draw the most stable product formed in the given reaction. **Reaction (a):** - **Starting Material:** A six-membered cyclic ester (lactone) with a propyl substituent. - **Reagents:** Sodium ethoxide (NaOEt) in ethanol (EtOH) and heat (Δ). **Reaction Details:** - The reaction involves the use of a strong base, NaOEt, in an alcoholic solvent, EtOH, often leading to an elimination or substitution process. - Heat is provided, indicating that the reaction might involve elimination, likely leading to the formation of an alkene. **Task:** - Using the drawing tools in the interface (lines for single bonds, double bonds, and rings), determine the most stable alkene product formed after the elimination reaction. - The reaction should be considered under thermodynamic control due to the presence of heat, suggesting the most substituted alkene is the favored product. ### Drawing Interface Explanation **Tools Available:** - **Select**: Choose this tool to highlight and manipulate parts of the structure. - **Draw**: Use this tool to add bonds: - **Single Bond (/)** - **Double Bond (=)** - **Triple Bond (≡)** - **Rings**: Utilize pre-defined rings for adding structures like cyclohexane or benzene. - **Atoms**: Click on “C”, “H”, or “O” to add carbon, hydrogen, or oxygen atoms specifically. Use these tools to depict the structure of the most stable product obtained from Reaction (a). Focus on forming a thermodynamically stable alkene with the base-induced elimination of a proton, resulting in a double bond within the ring or between ring substituents.
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