Draw the Lewis structure of IF2O2¯ (with minimized formal charges) and then determine the ideal bonding angle(s) of the central atom.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Title: Lewis Structure of IF₂O₂⁻ and Ideal Bond Angles**

**Objective:**
Learn how to draw the Lewis structure for IF₂O₂⁻ with minimized formal charges and determine the ideal bond angles at the central atom.

**Lewis Structure Explanation:**

- **Central Atom:** Iodine (I)
- Iodine is bonded to two fluorine (F) atoms and two oxygen (O) atoms. 
- Each fluorine atom is connected with a single bond and has three lone pairs of electrons.
- Each oxygen atom is connected to iodine by a double bond, with two lone pairs of electrons.
- The overall charge of the ion is -1.
- The structure displays formal charge minimization.

**Ideal Bond Angles:**

- The geometry around the iodine atom suggests bond angles of 90° and 120°.
  
**Answer Choices:**
- A) 109.5°
- **B) 90° and 120°** (Correct)
- C) 120°
- D) 30°
- E) 135°

The correct answer is highlighted: **B) 90° and 120°** which reflects the bond angles due to the trigonal bipyramidal arrangement around iodine, with lone pairs taking equatorial positions.
Transcribed Image Text:**Title: Lewis Structure of IF₂O₂⁻ and Ideal Bond Angles** **Objective:** Learn how to draw the Lewis structure for IF₂O₂⁻ with minimized formal charges and determine the ideal bond angles at the central atom. **Lewis Structure Explanation:** - **Central Atom:** Iodine (I) - Iodine is bonded to two fluorine (F) atoms and two oxygen (O) atoms. - Each fluorine atom is connected with a single bond and has three lone pairs of electrons. - Each oxygen atom is connected to iodine by a double bond, with two lone pairs of electrons. - The overall charge of the ion is -1. - The structure displays formal charge minimization. **Ideal Bond Angles:** - The geometry around the iodine atom suggests bond angles of 90° and 120°. **Answer Choices:** - A) 109.5° - **B) 90° and 120°** (Correct) - C) 120° - D) 30° - E) 135° The correct answer is highlighted: **B) 90° and 120°** which reflects the bond angles due to the trigonal bipyramidal arrangement around iodine, with lone pairs taking equatorial positions.
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