Draw the intermediate that is common to all three products for thre reaction of 2-butene in the presence of bromine gas (Br2 ), LICI, and methanol. Interactive 3D display mode

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Title: Common Intermediate in the Reaction of 2-Butene with Bromine, LiCl, and Methanol**

**Objective:**
To identify and draw the intermediate common to all three products formed when 2-butene reacts with bromine gas (\(Br_2\)), lithium chloride (LiCl), and methanol (\(MeOH\)).

**Reaction Process:**
The image illustrates the transformation of 2-butene in the presence of bromine, resulting in three products due to subsequent reactions with LiCl and methanol.

**Diagram Explanation:**
1. **Starting Material:**
   - **2-Butene** (\(H_3C-CH=CH-CH_3\)) is the alkene undergoing reaction.

2. **Reactants:**
   - **Bromine (\(Br_2\))** is added across the double bond of 2-butene.
   - **LiCl** and **methanol (\(MeOH\))** are additional reactants that influence product formation.

3. **Products:**
   - An intermediate bromonium ion forms initially, which then reacts to form three different products. The structures depicted indicate the presence of the bromonium ion and the final products which include:
     - A compound with a bromine atom and a methoxy group (Br and OCH₃).
     - A dibromo compound (Br and Br).
     - A compound containing bromine and chlorine (Br and Cl).

This example demonstrates the versatility and reactivity of 2-butene under halogen addition and substitution conditions. Visual aids like interactive 3D models can help in understanding the spatial orientation and mechanism of these reactions.
Transcribed Image Text:**Title: Common Intermediate in the Reaction of 2-Butene with Bromine, LiCl, and Methanol** **Objective:** To identify and draw the intermediate common to all three products formed when 2-butene reacts with bromine gas (\(Br_2\)), lithium chloride (LiCl), and methanol (\(MeOH\)). **Reaction Process:** The image illustrates the transformation of 2-butene in the presence of bromine, resulting in three products due to subsequent reactions with LiCl and methanol. **Diagram Explanation:** 1. **Starting Material:** - **2-Butene** (\(H_3C-CH=CH-CH_3\)) is the alkene undergoing reaction. 2. **Reactants:** - **Bromine (\(Br_2\))** is added across the double bond of 2-butene. - **LiCl** and **methanol (\(MeOH\))** are additional reactants that influence product formation. 3. **Products:** - An intermediate bromonium ion forms initially, which then reacts to form three different products. The structures depicted indicate the presence of the bromonium ion and the final products which include: - A compound with a bromine atom and a methoxy group (Br and OCH₃). - A dibromo compound (Br and Br). - A compound containing bromine and chlorine (Br and Cl). This example demonstrates the versatility and reactivity of 2-butene under halogen addition and substitution conditions. Visual aids like interactive 3D models can help in understanding the spatial orientation and mechanism of these reactions.
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