Draw the free body diagram, the normal force, and x and y component of the forces directed at an angle. 200 N 30.0 F- 150 N Fs
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![Draw the free body diagram, the normal force, and x and y component of the
forces directed at an angle.
200 N
30.0
Fy = 150 N
Fx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faef92fef-4656-4fa1-8534-601bfec491c1%2F92004fa2-4aa1-44f6-8ef8-ebcbb91c8b8b%2Fxund4vs_processed.png&w=3840&q=75)
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- An object is moving to the right in a straight line. The net force acting on the object is also directed to the right, but the magnitude of the force is decreasing with time. The object will... A. continue to move to the right with a constant speed stop and then begin moving to the left. continue to move to the right, with its speed decreasing with time D. continue to move to the right, with its speed increasing with time.A diagram represents a cart moving on a ramp. Assuming a frictional force of 12.2N. what is the magnitude of the net force acting on the cart.Only two horizontal forces act on a 6.8 kg body. One force is 7.9 N, acting due east, and the other is 6.6 N, acting 40° north of west. What is the magnitude of the body's acceleration? Number i Units
- 2. You are moving the box (m=1Okg) across a rough floor by pushing on it at an angle of 20° below the horizontal with force of magnitude F=100N. What is the coefficient of kinetic friction between the box and the floor if it is moving at constant velocity? Present free-body diagram. 10°339 8 20 A 20 kg box is resting on horizontal surface initially. Then a F =50 N force pulls on the angle of 20 degrees above horizontal. The kinetic frictional coefficient is 0.20. 6. What is the horizontal component of the force Fx ? box by a cord at an FN =soNo a 47 N C. 18.2 N b. 17.1 N d. 29 N Fx 7. What is the normal force acting on the box? 777 c. 196 N a. 47 N b. 179 N d. 125 N M9i'm doing chapter 4 problem 12p in the college physics 11th edition text book. On bartleby it says that "total force along the x axis is fx= f1sin30degrees - f2sin10degrees" my question is that wouldnt it be the cosine since it is the x axis and not sin?? i put a image below
- How to find the average force when only given two distances and two forces. Distance = 0m & 0.01m Force= 0N & 1.20NA 2.0 kg box is at rest on a flat horizontal surface. A continuously applied force is then exertedon the box. When the applied force just exceeds 5.0N the box then begins to move. Q1. Construct a free-body diagram for the box at the moment when the applied force is 5.0N. Q2. Determine the magnitude of the peak static friction force and the corresponding coefficientof static friction.The distance between two telephone poles is 44.0 m. When a 1.00-kg bird lands on the telephone wire midway between the poles, the wire sags 0.180 m. Draw a free-body diagram of the bird. How much tension does the bird produce in the wire? Ignore the weight of the wire.