Answered: F- 450N F.cos10 Fcos 30 F – 400 N 10 30… | bartleby

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i'm doing chapter 4 problem 12p in the college physics 11th edition text book. On bartleby it says that "total force along the x axis is fx= f1sin30degrees - f2sin10degrees" my question is that wouldnt it be the cosine since it is the x axis and not sin?? i put a image below

F - 450N
F.cos10
Fcos 30
E- 400 N
10
30
F. sin10
F sin 30°
The total force along the x-axis is,
Fx = F1 sin 30° – F2 sin 10°
Substitute 400 N for F1 and 400 N for F2 in the above expression.

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