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- If H* is eliminated from the carbocation shown here in an electrophile elimination step, then three possible constitutional isomers can form. Draw the mechanism for the formation of all three of those products. H2O + ?Provide the full radical mechanism with all arrows and intermediates shown in the following reaction.5. Each of the following may participate in an elimination reaction, under the proper conditions. (a) Circle the alpha (a) carbon. (b) Circle the beta (B) carbon(s). (c) Draw the alkene product(s) that may form, with the new double bond between the a and B positions. (d) If more than one alkene product is possible, circle the most stable (Zaitsev) product. X tx + 3
- Draw the mechanism arrows for both propagation steps for the radical addition of HBr to the alkene.Draw both resonance structures of the most stable carbocation intermediate in the reaction shown.Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the first step of this reaction sequence. Be sure to account for all bond-breaking and bond- making steps. I H BH₂ H B H Select to Add Arrows > H Bll H BH₂
- Help #12. The following carbocation is generated as an intermediate in the addition of H-Br to an alkene. Draw the structure of all possible alkenes that could have formed this intermediate.Consider the nucleophilic substitution reaction shown here. Based on the stereochemistry, does it proceed by an Sy1 or Sy2 mechanism? Explain. OH KOCH3 Enantiomer CH;OH `OCH3
- CO2 Follow the curved arrows and draw the product of this reaction. You do not have to consider stereochemistry.React each molecule with each of the substrates on the right include step by step reaction also inclue arrows and drawDraw the products of the reaction shown. Electron flow is indicated with curved arrows. H₂C CI: