Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw the arrow pushing mechanism of the following reaction
![**Transcription for Educational Website**
**Question 2: Arrow-Pushing Mechanism of a Reaction (10 points)**
In this problem, you are required to draw the arrow-pushing mechanism for the given reaction to illustrate the movement of electrons throughout the process.
**Reaction Details:**
- **Starting Material:** A molecule with an iodine (I) substituent.
- **Reagent:** Water (H₂O) and heat (Δ).
- **Product:** The molecule forms a double bond after the elimination of iodine.
**Explanation of the Reaction:**
The mechanism involves using water and heat to convert an alkyl iodide to an alkene. The arrow-pushing mechanism should demonstrate the appropriate steps for:
1. **Formation of the Carbocation:** The iodine group leaves, resulting in a carbocation formation.
2. **Rearrangement (if necessary):** Check for any possible rearrangements to form a more stable carbocation.
3. **Deprotonation:** A base (often the water or OH⁻ formed) removes a hydrogen atom, forming a double bond and ejecting the iodide ion.
The final molecule exhibits a newly formed double bond in place of the iodine substituent, producing an alkene. The arrows in the mechanism should clearly show the flow of electrons in each step.
**Diagram Explanation:**
- The left side of the diagram shows the starting material, a tertiary alkyl iodide.
- The arrow indicates the direction of the reaction left to right, with the reagents H₂O and heat shown above the arrow.
- The right side shows the product, an alkene, depicting the formation of a double bond between two carbon atoms where iodine was initially attached.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fe4c5ff-3153-480d-9c91-a45f42309b22%2F624747aa-0933-4756-9bdd-305742ea4a56%2Fgzclewe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website**
**Question 2: Arrow-Pushing Mechanism of a Reaction (10 points)**
In this problem, you are required to draw the arrow-pushing mechanism for the given reaction to illustrate the movement of electrons throughout the process.
**Reaction Details:**
- **Starting Material:** A molecule with an iodine (I) substituent.
- **Reagent:** Water (H₂O) and heat (Δ).
- **Product:** The molecule forms a double bond after the elimination of iodine.
**Explanation of the Reaction:**
The mechanism involves using water and heat to convert an alkyl iodide to an alkene. The arrow-pushing mechanism should demonstrate the appropriate steps for:
1. **Formation of the Carbocation:** The iodine group leaves, resulting in a carbocation formation.
2. **Rearrangement (if necessary):** Check for any possible rearrangements to form a more stable carbocation.
3. **Deprotonation:** A base (often the water or OH⁻ formed) removes a hydrogen atom, forming a double bond and ejecting the iodide ion.
The final molecule exhibits a newly formed double bond in place of the iodine substituent, producing an alkene. The arrows in the mechanism should clearly show the flow of electrons in each step.
**Diagram Explanation:**
- The left side of the diagram shows the starting material, a tertiary alkyl iodide.
- The arrow indicates the direction of the reaction left to right, with the reagents H₂O and heat shown above the arrow.
- The right side shows the product, an alkene, depicting the formation of a double bond between two carbon atoms where iodine was initially attached.
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