Draw the arrow pushing mechanism of the following reaction

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Draw the arrow pushing mechanism of the following reaction 

**Transcription for Educational Website**

**Question 2: Arrow-Pushing Mechanism of a Reaction (10 points)**

In this problem, you are required to draw the arrow-pushing mechanism for the given reaction to illustrate the movement of electrons throughout the process.

**Reaction Details:**

- **Starting Material:** A molecule with an iodine (I) substituent.
- **Reagent:** Water (H₂O) and heat (Δ).
- **Product:** The molecule forms a double bond after the elimination of iodine.

**Explanation of the Reaction:**

The mechanism involves using water and heat to convert an alkyl iodide to an alkene. The arrow-pushing mechanism should demonstrate the appropriate steps for:

1. **Formation of the Carbocation:** The iodine group leaves, resulting in a carbocation formation.

2. **Rearrangement (if necessary):** Check for any possible rearrangements to form a more stable carbocation.

3. **Deprotonation:** A base (often the water or OH⁻ formed) removes a hydrogen atom, forming a double bond and ejecting the iodide ion.

The final molecule exhibits a newly formed double bond in place of the iodine substituent, producing an alkene. The arrows in the mechanism should clearly show the flow of electrons in each step.

**Diagram Explanation:**
- The left side of the diagram shows the starting material, a tertiary alkyl iodide.
- The arrow indicates the direction of the reaction left to right, with the reagents H₂O and heat shown above the arrow.
- The right side shows the product, an alkene, depicting the formation of a double bond between two carbon atoms where iodine was initially attached.
Transcribed Image Text:**Transcription for Educational Website** **Question 2: Arrow-Pushing Mechanism of a Reaction (10 points)** In this problem, you are required to draw the arrow-pushing mechanism for the given reaction to illustrate the movement of electrons throughout the process. **Reaction Details:** - **Starting Material:** A molecule with an iodine (I) substituent. - **Reagent:** Water (H₂O) and heat (Δ). - **Product:** The molecule forms a double bond after the elimination of iodine. **Explanation of the Reaction:** The mechanism involves using water and heat to convert an alkyl iodide to an alkene. The arrow-pushing mechanism should demonstrate the appropriate steps for: 1. **Formation of the Carbocation:** The iodine group leaves, resulting in a carbocation formation. 2. **Rearrangement (if necessary):** Check for any possible rearrangements to form a more stable carbocation. 3. **Deprotonation:** A base (often the water or OH⁻ formed) removes a hydrogen atom, forming a double bond and ejecting the iodide ion. The final molecule exhibits a newly formed double bond in place of the iodine substituent, producing an alkene. The arrows in the mechanism should clearly show the flow of electrons in each step. **Diagram Explanation:** - The left side of the diagram shows the starting material, a tertiary alkyl iodide. - The arrow indicates the direction of the reaction left to right, with the reagents H₂O and heat shown above the arrow. - The right side shows the product, an alkene, depicting the formation of a double bond between two carbon atoms where iodine was initially attached.
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