**Understanding Reactions of 1-Bromopropene and Propenoic Acid**1. **Addition of HCl to 1-Bromopropene** - Reaction: \( \text{CH}_3\text{CH}=\text{CHBr} + \text{HCl} \rightarrow \text{CH}_3\text{CH}_2\text{CHBrCl} \) - Reactants: 1-Bromopropene - Product: 1-Bromo-1-chloropropane - Explanation: The addition of HCl to 1-bromopropene results in the exclusive formation of 1-bromo-1-chloropropane.2. **Reaction of Propenoic Acid with HCl** - Reaction: \[ \text{CH}_2=\text{CHCOOH} + \text{HCl} \rightarrow \text{ClCH}_2\text{CH}_2\text{COOH} \] - Reactants: Propenoic acid (acrylic acid) - Product: 3-Chloropropanoic acid - Note: 2-Chloropropanoic acid is not formed. - Explanation: Treating propenoic acid with HCl exclusively yields 3-chloropropanoic acid, avoiding the formation of the 2-chloro isomer.3. **Structural Formulas for Alkene Reaction with Br\(_2\) and Water** - Problem: Draw the structural formula for an alkene with the molecular formula \( \text{C}_5\text{H}_{10} \) that reacts with Br\(_2\) and water to give each product. - Options: - (a) A structure with a hydroxyl group (\(\text{OH}\)) and a bromine atom (\(\text{Br}\)) on adjacent carbon atoms. - (b) A structure showing a similar arrangement. - (c) Another possible arrangement with different positioning of \(\text{OH}\) and \(\text{Br}\).These reactions illustrate the selectivity of addition reactions with alkenes and the importance of molecular structure in determining product formation.

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Answered: Draw a structural formula for the…

Draw a structural formula for the alkene with the molecular formula C-H₁0 that reacts with Br, and water to give each product. Br (a) OH (b) OH Br (c) HO Br

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Designing a Synthesis

Organic synthesis is a branch of chemical synthesis that involves the planned construction of organic compounds/molecules from smaller units that possess functional groups. Friedrich Wöhler was the first scientist who designed the synthesis of an organic compound, urea from inorganic starting materials silver cyanate with ammonium chloride via a simple, one-step synthesis.

Question

**Understanding Reactions of 1-Bromopropene and Propenoic Acid**

1. **Addition of HCl to 1-Bromopropene**
- Reaction: \( \text{CH}_3\text{CH}=\text{CHBr} + \text{HCl} \rightarrow \text{CH}_3\text{CH}_2\text{CHBrCl} \)
- Reactants: 1-Bromopropene
- Product: 1-Bromo-1-chloropropane
- Explanation: The addition of HCl to 1-bromopropene results in the exclusive formation of 1-bromo-1-chloropropane.

2. **Reaction of Propenoic Acid with HCl**
- Reaction:
\[ \text{CH}_2=\text{CHCOOH} + \text{HCl} \rightarrow \text{ClCH}_2\text{CH}_2\text{COOH} \]
- Reactants: Propenoic acid (acrylic acid)
- Product: 3-Chloropropanoic acid
- Note: 2-Chloropropanoic acid is not formed.
- Explanation: Treating propenoic acid with HCl exclusively yields 3-chloropropanoic acid, avoiding the formation of the 2-chloro isomer.

3. **Structural Formulas for Alkene Reaction with Br\(_2\) and Water**
- Problem: Draw the structural formula for an alkene with the molecular formula \( \text{C}_5\text{H}_{10} \) that reacts with Br\(_2\) and water to give each product.
- Options:
- (a) A structure with a hydroxyl group (\(\text{OH}\)) and a bromine atom (\(\text{Br}\)) on adjacent carbon atoms.
- (b) A structure showing a similar arrangement.
- (c) Another possible arrangement with different positioning of \(\text{OH}\) and \(\text{Br}\).

These reactions illustrate the selectivity of addition reactions with alkenes and the importance of molecular structure in determining product formation.

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