Draw a state diagram of a Turing machine (TM) recognizing the fol- lowing language over the alphabet E = {0, 1, >}. L = {x >y : 1,y E L(1(0U1)*) ^ bin(r) is a power of 2 A bin(xr) > bin(y)}, where bin(r) is the value of r viewed as a binary number. Note that besides edge labels like 0 → 1, R, we allow abbreviations like 0 → R, standing for 0 → 0, R, and 0,1 → R, standing for 0 → 0, R, 1 → 1, R.
Draw a state diagram of a Turing machine (TM) recognizing the fol- lowing language over the alphabet E = {0, 1, >}. L = {x >y : 1,y E L(1(0U1)*) ^ bin(r) is a power of 2 A bin(xr) > bin(y)}, where bin(r) is the value of r viewed as a binary number. Note that besides edge labels like 0 → 1, R, we allow abbreviations like 0 → R, standing for 0 → 0, R, and 0,1 → R, standing for 0 → 0, R, 1 → 1, R.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![Draw a state diagram of a Turing machine (TM) recognizing the fol-
lowing language over the alphabet E = {0, 1, >}.
L = {x >y : 1,y E L(1(0U1)*) ^ bin(r) is a power of 2 A bin(xr) > bin(y)},
where bin(r) is the value of r viewed as a binary number.
Note that besides edge labels like 0 → 1, R, we allow abbreviations
like 0 → R, standing for 0 → 0, R,
and 0,1 → R, standing for 0 → 0, R, 1 → 1, R.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b8f2041-e50a-4e46-9284-5dc0f6456a77%2F7f490fd2-f014-447c-aacd-dfce4a688b10%2Fwixeldl_processed.png&w=3840&q=75)
Transcribed Image Text:Draw a state diagram of a Turing machine (TM) recognizing the fol-
lowing language over the alphabet E = {0, 1, >}.
L = {x >y : 1,y E L(1(0U1)*) ^ bin(r) is a power of 2 A bin(xr) > bin(y)},
where bin(r) is the value of r viewed as a binary number.
Note that besides edge labels like 0 → 1, R, we allow abbreviations
like 0 → R, standing for 0 → 0, R,
and 0,1 → R, standing for 0 → 0, R, 1 → 1, R.
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