You need to show detail work on how you get the answer. Dont use answers from other websites please! Please type your answer not picture 3. Suppose that a 32M x 16 main memory is built using 512K × 8 RAM chips and memory is word-addressable.  a) How many RAM chips are necessary?   Number of RAM Chips = Memory Size/ Chip Size =225x 16/219x 8 =27   128 RAM chips Needed b) If we were accessing one full word, how many chips would be involved? As given RAM chips holds 8 bits ( 512K × 8)for a word. Main memory holds 16 bits (32M * 16 ). So that design needs 16 bit word which means two byes. And chip hold only 1 byte. So that 2 chips would be involved to access one word c) How many address bits are needed for each RAM chip? For 512K × 8 chip, bits required are 512K =>512 x 1024 = 29x 210 = 219 219 bits required. And 19 address bits are required for each chip.

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You need to show detail work on how you get the answer.

Dont use answers from other websites please!

Please type your answer not picture

3. Suppose that a 32M x 16 main memory is built using 512K × 8 RAM chips and memory is word-addressable. 

a) How many RAM chips are necessary?  

Number of RAM Chips = Memory Size/ Chip Size

=225x 16/219x 8

=27

  128 RAM chips Needed

b) If we were accessing one full word, how many chips would be involved?

  • As given RAM chips holds 8 bits ( 512K × 8)for a word. Main memory holds 16 bits (32M * 16 ).
  • So that design needs 16 bit word which means two byes. And chip hold only 1 byte.
  • So that 2 chips would be involved to access one word

c) How many address bits are needed for each RAM chip?

For 512K × 8 chip, bits required are 512K

=>512 x 1024 = 29x 210 = 219

219 bits required.

And 19 address bits are required for each chip.

d) How many banks will this memory have?

The number of banks = main memory addressable / chip addressable items

So that, no. of Banks = 225 / 2 19

=26 = 64 Banks

Therefore, the number of banks equals 64

e) How many address bits are needed for all of the memory?

The number of bits required for memory is 32 M = 25x 210x 210

=225

Therefore, 25 bits are needed to address the main memory.

f) If high-order interleaving is used, where would address 32(base 10) be located? (Your answer should be "Bank#, Offset#")
g) Repeat (f) for low-order interleaving.

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 Draw a diagram of the 128M x 16 chip built from 32M x 8 chips. Include the range of
addresses for each chip.

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What size decoder is needed to construct an 128M x 16 chip from 32M x 8 chips? 

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