Draw a DFA
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Draw a DFA that accepts the following language over the alphabet {0,1}: the set of all strings such that any substring of four consecutive symbols does not have exactly two 0s.
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- In C language, implement the following two functions that allow breaking a string into non-empty tokens using a given delimiter. For example, For a string "abc-EFG-hi", and a delimiter '-': the list of tokens is ["abc", "EFG", "hi"] For a string "abc-EFG---hi-", and a delimiter '-': the list of tokens is ["abc", "EFG", "hi"] For a string "abc", and a delimiter ' ': the list of tokens is ["abc"] For a string "++abc++", and a delimiter '+': the list of tokens is ["abc"] That is, we break the string using the given delimiter, and the tokens are only the non-empty substrings. 1. The function count_tokens gets a string str, and a char delim, and returns the number of tokens in the string separated by delim. int count_tokens(const char* str, char delim); For example count_tokens("abc-EFG--", '-') needs to return 2. count_tokens("++a+b+c", '+') needs to return 3. count_tokens("***", '*') needs to return 0. 2. The function get_tokens gets a string str, and a char delim, and returns the…Let s be a string of length 2 with characters from {0, 1, 2}, and define statements a, b, c, and d as follows:a = “the first character of s is 0”b = “the first character of s is 1”c = “the second character of s is 1”d = “the second character of s is 2”. Describe the set of all strings for which each of the following is true.A uwuified sentence is sentence that has been transformed using a made-up Internet language in which some of the letters in the words are replaced by something else. The exact scheme is described below: Any uppercase/lowercase R or L is replaced by w/w, respectively. • If we encounter an o/o in a word, check if the previous letter (if it exists) is an M/m or N/n. If the previous letter is one of these, insert the lowercase letter y in between them, regardless of the capitalization of the other letters. • All other characters are left unchanged. Some examples: Professor will be converted to Pwofessow (There are two r's that are replaced by w's. Since the two o's aren't proceeded by an M/n or N/n, no y will be inserted.) LLunoacyo will be converted to wwunyoacyo (The two L's will be replaced with two ws according to the first rule. Then the first o will have a y inserted in front of it between then and the o according to the second rule. The last o won't have a y inserted in between…
- Consider the alphabet set Σ = {a b}; Write Regular Expressions for the following definitions. 7. Language of All those words whose length is odd and they contain ab.8. Language of All those words which ends with bb and have odd length.9. Language of All those words which do not end with ba.A. Give a CFG G that generates all odd length strings over {a,b}.B. Give a Push-down Automaton that accepts strings generated by G in Part a.Construct a set S of strings in lowercase (R = 26) for which the R-way trie uses space (in words) less than the total number of characters in strings in S. (The number of characters in the set {abc, bcd, aabd} is 10.)
- Write a regular expression for the set of strings over the alphabet {a, b} that have at least one a andat least one b. For example, aaaba and bbaba are strings in the set, but aaaa and bbb are not.Implement the following two functions that allow breaking a string into non-empty tokens using a given delimiter in c language . For example, ● For a string “abc-EFG-hi”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc-EFG---hi-”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc”, and a delimiter ‘ ’ : the list of tokens is [“abc”] ● For a string “++abc++”, and a delimiter ‘+’ : the list of tokens is [“abc”] That is, we break the string using the given delimiter, and the tokens are only the non-empty substrings.Implement the following two functions that allow breaking a string into non-empty tokens using a given delimiter in c language . For example, ● For a string “abc-EFG-hi”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc-EFG---hi-”, and a delimiter ‘-’ : the list of tokens is [“abc”, “EFG”, “hi”] ● For a string “abc”, and a delimiter ‘ ’ : the list of tokens is [“abc”] ● For a string “++abc++”, and a delimiter ‘+’ : the list of tokens is [“abc”] That is, we break the string using the given delimiter, and the tokens are only the non-empty substrings. The function count_tokens gets a string str, and a char delim, and returns the number of tokens in the string separated by delim. int count_tokens(const char* str, char delim); For example● count_tokens("abc-EFG--",'-')needstoreturn2. ● count_tokens("++a+b+c",'+')needstoreturn3.● count_tokens("***",'*')needstoreturn0.The function get_tokens gets a string str, and a char delim, and returns the…
- Count the number of strings of length 5 over A = {a, b, c, d} that begins with a, ends with d and have exactly two b’s.Draw a DFA over the alphabet {a,b,c}that only accepts strings with no c’s and an even number of a’s, or an odd number of c’s and an odd number of b’s. For example, it should accept aa, aba, abbabaa, cbacabcb, cbcca, and abc but not aca, bacc, or aaa.Draw NFA that accepts the set of strings over {a, b} such that there should be at least one substring which starts and ends with a b and the number of symbols between these two b’s is divisible by 4. Example: abababaaaababab, babbaa (since 0 is divisible by 4), ababababbaa.l