Drag and Drop the correct answers in the blanks. A mass mis hanging from the end of a vertical spring that has a spring constant k. The equilibrium position of the mass, yo, is The total potential energy of the mass when it displaced by s from the equilibrium position is given by e U(s) =-ks +- mgyo
Drag and Drop the correct answers in the blanks. A mass mis hanging from the end of a vertical spring that has a spring constant k. The equilibrium position of the mass, yo, is The total potential energy of the mass when it displaced by s from the equilibrium position is given by e U(s) =-ks +- mgyo
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![Drag and Drop the correct answers in the blanks.
A mass mis hanging from the end of a vertical spring that has a
spring constant k. The equilibrium position of the mass, y,, is
The total potential energy of the mass when it
is displaced by s from the equilibrium position is given by
1
+ U(s)
ks+-
2
1.
1.
= ks°
+ U(s) = ks+ mgyo
2.
+ is zero
+ negative
+ U(s)
2
2]
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0d2b672-42e0-425d-b22f-b4d7c22ab430%2F88a3dbf6-533e-4efa-8c15-d41ad579e274%2Fa9fxb5h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Drag and Drop the correct answers in the blanks.
A mass mis hanging from the end of a vertical spring that has a
spring constant k. The equilibrium position of the mass, y,, is
The total potential energy of the mass when it
is displaced by s from the equilibrium position is given by
1
+ U(s)
ks+-
2
1.
1.
= ks°
+ U(s) = ks+ mgyo
2.
+ is zero
+ negative
+ U(s)
2
2]
2
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