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doctor in Oklahoma City wants to know whether the average life s Four hospitals in the city differ. The data below represents the life sp patients from each hospital. Perform an ANOVA test with a 10% leve the average life span of heart disease patients in Oklahoma City diffe that treats them

doctor in Oklahoma City wants to know whether the average life s Four hospitals in the city differ. The data below represents the life sp patients from each hospital. Perform an ANOVA test with a 10% leve the average life span of heart disease patients in Oklahoma City diffe that treats them

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 ▼ Part 1 of 4 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital 4: 29.7, 6.1, 8.5, 2.8, 9.9, 13.6, 3, 2.2, 4, 9.7, 18, 5.4, 10.4, 10.5, 0.6, 0.6, 1.6, 7.9, 4.8, 12.2, 2.9, 9.9, 8.2, 2.2, 4, 6.8, 14.8, 11.4, 5.8, 8.4, 11.4 Step 1: State the null and alternative hypotheses. Ho: P₁= H, H₂ = P₁ Ha: At least one mean isn't equal to the other means Part 2 of 4 Step 2: Assuming the null hypothesis is true, determine the features of the distribution of test statistics. We will use a(n) F dfbetween = Question Help: D Post to forum Submit Part ✓✓distribution with numerator degrees of freedom and denominator degrees of freedom dfwithin = MacBook Pro
Transcribed Image Text:A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 ▼ Part 1 of 4 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital 4: 29.7, 6.1, 8.5, 2.8, 9.9, 13.6, 3, 2.2, 4, 9.7, 18, 5.4, 10.4, 10.5, 0.6, 0.6, 1.6, 7.9, 4.8, 12.2, 2.9, 9.9, 8.2, 2.2, 4, 6.8, 14.8, 11.4, 5.8, 8.4, 11.4 Step 1: State the null and alternative hypotheses. Ho: P₁= H, H₂ = P₁ Ha: At least one mean isn't equal to the other means Part 2 of 4 Step 2: Assuming the null hypothesis is true, determine the features of the distribution of test statistics. We will use a(n) F dfbetween = Question Help: D Post to forum Submit Part ✓✓distribution with numerator degrees of freedom and denominator degrees of freedom dfwithin = MacBook Pro
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