do a program HTML, CSS, and JavaScript to solve 3 input numbers using quadratic equation using the algorithm 1) Start of program 2) Input the coefficients of the equation numbers, a, b and c from the user. 3) Calculate discriminant = (b * b) – (4 * a * c) 4) If discriminant > 0: Calculate root1 = ( -b + sqrt(discriminant)) / (2 * a) Calculate root2 = ( -b - sqrt(discriminant)) / (2 * a) Print “Roots are real and different” Print root1 and root2 5) Otherwise if discriminant = 0: Calculate root1 = -b / (2 *a) root2 = root1 Print “Root are real and equal” Print root1 and root2 6) Otherwise : Calculate real = -b / (2 * a) Calculate imaginary = sqrt(-discriminant) / (2 * a) Print “Roots are imaginary” Print real, “±” , imaginary, “i” 7)End of program
do a program HTML, CSS, and JavaScript to solve 3 input numbers using quadratic equation using the algorithm 1) Start of program 2) Input the coefficients of the equation numbers, a, b and c from the user. 3) Calculate discriminant = (b * b) – (4 * a * c) 4) If discriminant > 0: Calculate root1 = ( -b + sqrt(discriminant)) / (2 * a) Calculate root2 = ( -b - sqrt(discriminant)) / (2 * a) Print “Roots are real and different” Print root1 and root2 5) Otherwise if discriminant = 0: Calculate root1 = -b / (2 *a) root2 = root1 Print “Root are real and equal” Print root1 and root2 6) Otherwise : Calculate real = -b / (2 * a) Calculate imaginary = sqrt(-discriminant) / (2 * a) Print “Roots are imaginary” Print real, “±” , imaginary, “i” 7)End of program
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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do a
1) Start of program
2) Input the coefficients of the equation numbers, a, b and c from the user.
3) Calculate discriminant = (b * b) – (4 * a * c)
4) If discriminant > 0:
- Calculate root1 = ( -b + sqrt(discriminant)) / (2 * a)
- Calculate root2 = ( -b - sqrt(discriminant)) / (2 * a)
- Print “Roots are real and different”
- Print root1 and root2
5) Otherwise if discriminant = 0:
- Calculate root1 = -b / (2 *a)
- root2 = root1
- Print “Root are real and equal”
- Print root1 and root2
6) Otherwise :
- Calculate real = -b / (2 * a)
- Calculate imaginary = sqrt(-discriminant) / (2 * a)
- Print “Roots are imaginary”
- Print real, “±” , imaginary, “i”
7)End of program
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