Discrete MathQ: ) Prove the distributive laws (DL1)DL1 set photo have been uploaded below Distributive Laws for Propositional Logic( DL1) α V (βΛγ) (α ν β ) Λ (α V γ). (DL2) α Λ βV γ) (α Λ β) V ( α Λ γ)Perfectly symmetric:• swapping A and V turn either law into the other.Closely related to Distributed Laws for sets (Chapt 5)

Answered: (DL1) α V (βΛ γ)-(α V β) Λ(α V γ)

Engineering

Computer Engineering

(DL1) α V (βΛ γ)-(α V β) Λ(α V γ)

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Please do not give solution in image format thanku # Question 2 # Say we want to find the total population of a city.# The city can be divided into an m x n grid of neighborhoods where each neighborhood has a# certain number of buildings.# Conveniently due to zoning laws, all buildings within a neighborhood must have the s# ame number of people. # Inconveniently, in the data a column of buildings per neighborhood is followed by a# column of people per building. For example: toy_city_data = np.array([[11, 3, 8, 4],[7, 2, 15, 1]])# # bldgs # ppl # bldgs # ppl # The toy city above is a 2 x 2 city.# The buildings per neighborhood matrix looks like num_buildings = np.array([[11, 8],[7, 15]]) # The people per building looks like num_people_per_building = np.array([[3, 4],[2, 1]]) # Then the total population of the city is:# 11*3 + 8*4 + 7*2 + 15*1# Find the average number of people in each neighborhood of the city from the `city_data`# variable below. city_data = np.array([[34, 1, 16, 3, 26,…
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Analysis: (Describe the problem including input and output in your own words.) Design: (Describe the major steps for solving the problem.) Coding: (Go over your code step by step) Testing: (Describe how you test this program). In other words run your code with sample outputs Analysis of the problem: There is a rectangle with vertices a,b,c,d(let). The position of the vertices are : a=(-5,2.5) b=(-5,-2.5) c=(5,-2.5) d=(5,2.5) The centre of the rectangle is (0,0). Now a point x,y would be given by the user and the program concludes whether the point x,y is within the rectangle or not. The approach of the java code: Take the input of the 2D coordinates from the user. Check whether the horizontal distance is between -5 to 5 and the vertical distance is between -2.5 to 2.5. If the condition is true print the coordinate within the given rectangle. Otherwise print it is not in the rectangle. import java.util.*; class Main{ public static void main(String [] args){ Scanner…
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