The output of the program: Here the point (2,2) is within the rectangle in terms of horizontal and vertical distances. Here the point (6,4) is not in the rectangle as the horizontal distance is greater than 5.

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Analysis:

(Describe the problem including input and output in your own words.)

Design:

(Describe the major steps for solving the problem.)

Coding: (Go over your code step by step) 

Testing: (Describe how you test this program).  In other words run your code with sample outputs

Analysis of the problem:

There is a rectangle with vertices a,b,c,d(let). The position of the vertices are :

a=(-5,2.5)

b=(-5,-2.5)

c=(5,-2.5)

d=(5,2.5)

The centre of the rectangle is (0,0). Now a point x,y would be given by the user and the program concludes whether the point x,y is within the rectangle or not.

The approach of the java code:

  1. Take the input of the 2D coordinates from the user.
  2. Check whether the horizontal distance is between -5 to 5 and the vertical distance is between -2.5 to 2.5.
  3. If the condition is true print the coordinate within the given rectangle.
  4. Otherwise print it is not in the rectangle.

import java.util.*;

class Main{

    public static void main(String [] args){

        Scanner sc=new Scanner(System.in);

       

        // Taking the input of the points from the user

        System.out.print("Enter a point with two coordinates: ");

        // Declaring the x,y coordinates for the points

        double x=sc.nextDouble();

        double y=sc.nextDouble();

       

        //printing the position of the point

        System.out.print("Point("+x+","+y+") ");

 

        // checking if the given point is within the rectangle or not

        if(x>=-5 && x<=5 && y>=-2.5 && y<=2.5)

            System.out.print("is in the rectangle");

        else

            System.out.print("is not in the rectangle");

       

    }

}

The output of the program:

Here the point (2,2) is within the rectangle in terms of horizontal and vertical distances.

Here the point (6,4) is not in the rectangle as the horizontal distance is greater than 5.

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