Dissolve 0.25g NaCi, 0.20g NaHCO3, 0.35g KCI, and 1.5g of glucose in 100 ml distilled water using a 250 mL capacity beaker. Use the formula to create a 60 mL ORS. Based on the given procedure, calculate the total amount of potassium in the prepared solution. (MW: Na: 23, K: 39, CI: 35, H: 1, C: 12, 0: 16) 47.30 mmolVL 66.91 mmol/L 83.33 mmol/L O 71.11 mmol/L 23.81 mmol/L O 90.40 mmol/L

Dissolve 0.25g NaCi, 0.20g NaHCO3, 0.35g KCI, and 1.5g of glucose in 100 ml distilled water using a 250 mL capacity beaker. Use the formula to create a 60 mL ORS. Based on the given procedure, calculate the total amount of potassium in the prepared solution. (MW: Na: 23, K: 39, CI: 35, H: 1, C: 12, 0: 16) 47.30 mmolVL 66.91 mmol/L 83.33 mmol/L O 71.11 mmol/L 23.81 mmol/L O 90.40 mmol/L

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Dissolve 0.25g NaCi, 0.20g NaHCO3, 0.35g KCI, and 1.5g of glucose in 100 ml distilled water using a 250 mL capacity
beaker. Use the formula to create a 60 mL ORS.
Based on the given procedure, calculate the total amount of potassium in the prepared solution.
(MW: Na: 23, K: 39, CI: 35, H: 1, C: 12, O: 16)
47.30 mmol/L
66.91 mmol/L
O 83.33 mmol/L
O 71.11 mmol/L
O 23.81 mmol/L
O 90.40 mmol/L

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