Disk mass M pivot R M swinging motion A disk of mass M and radius R has a moment of inertia about its center of mass of ½ MR². Icom A tiny hole is drilled through the disk at the location shown (at 3/5 R ) and a pin is inserted into the hole to act as a pivot axis. The disk oscillates as a physical pendulum about the pin with a small angle of oscillation. Question: What is the approximate oscillation frequency of the disk? O w = ( 6g / (5R) )½ Ow = (g/ (2R))'½ w = ( 30g / (43R) )½ Ow = ( 18g / (29R) )½ None of the other answers is correct
Disk mass M pivot R M swinging motion A disk of mass M and radius R has a moment of inertia about its center of mass of ½ MR². Icom A tiny hole is drilled through the disk at the location shown (at 3/5 R ) and a pin is inserted into the hole to act as a pivot axis. The disk oscillates as a physical pendulum about the pin with a small angle of oscillation. Question: What is the approximate oscillation frequency of the disk? O w = ( 6g / (5R) )½ Ow = (g/ (2R))'½ w = ( 30g / (43R) )½ Ow = ( 18g / (29R) )½ None of the other answers is correct
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Transcribed Image Text:Disk mass M
pivot
M
swinging
motion
A disk of mass M and radius R has a moment of inertia about its center of mass of
Icom
12 MR2.
A tiny hole is drilled through the disk at the location shown (at 3/5 R ) and a pin is
inserted into the hole to act as a pivot axis. The disk oscillates as a physical
pendulum about the pin with a small angle of oscillation.
Question: What is the approximate oscillation frequency of the disk?
w = ( 6g / (5R) )½
w = ( g / (2R) )½
( 30g / (43R) )½
W =
= ( 18g / (29R) )½
O None of the other answers is correct
= ( 3g / (5R) )½
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