disk, drying the disk at 105°C, and igniting the residue by placing the dried sample in a muffle furnace at static (?). The following masses are recorded: Volume of sample: 30 mL Mass of filter disk: 0.1170 g a) The total suspended solids content is: • Mass of disk and dry solids: 0.1278 g • Mass of disk and ignited solids: 0.12489 g b) The volatile suspended solids content is: c) The fixed suspended solids content is:

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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2. The suspended solids content is determined by filtering a portion of the sample through a glass-fiber filter
disk, drying the disk at 105°C, and igniting the residue by placing the dried sample in a muffle furnace at
static (?). The following masses are recorded:
• Volume of sample: 30 mL
• Mass of filter disk: 0.1170 g
a) The total
suspended solids
content is:
b) The volatile
suspended solids
content is:
Mass of disk and dry solids: 0.1278 g
Mass of disk and ignited solids: 0.12489 g
c) The fixed
suspended solids
content is:
Transcribed Image Text:2. The suspended solids content is determined by filtering a portion of the sample through a glass-fiber filter disk, drying the disk at 105°C, and igniting the residue by placing the dried sample in a muffle furnace at static (?). The following masses are recorded: • Volume of sample: 30 mL • Mass of filter disk: 0.1170 g a) The total suspended solids content is: b) The volatile suspended solids content is: Mass of disk and dry solids: 0.1278 g Mass of disk and ignited solids: 0.12489 g c) The fixed suspended solids content is:
Expert Solution
Step 1: Data given:

The volume of the sample, V = 30 mL

mass of filter dish, straight w subscript 1 equals 0.1170 space straight g

mass of dish+ dry solid, w subscript 2 equals 0.1278 space g

mass of sish+ ignited solid, straight w subscript 3 equals 0.1248 space straight g

To find:

a) Total suspended solids

b) Volatile suspended solids

c) Fixed suspended solids

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