Q1: A conventional ASP is to be used for treatment of 10,000 m³/d of municipal wastewater. The influent BOD to the ASP is 160 mg/l. As per requirements, the effluent from the ASP should have a soluble BOD of not more than 10 mg/l. Assuming: MLSS=2500 mg/l Mean cell residence time = 10 d Return sludge from SST = 8000 mg/l Yield coefficient = 0.8 kg/kg Endogenous decay rate constant = 0.06 d-¹ Determine: Question i. The volume of aeration tank ii. The mass and volume of sludge to be wasted per day iii. The recycle ratio iv. Food to microorganism ratio

Q1: A conventional ASP is to be used for treatment of 10,000 m³/d of municipal wastewater. The influent BOD to the ASP is 160 mg/l. As per requirements, the effluent from the ASP should have a soluble BOD of not more than 10 mg/l. Assuming: MLSS=2500 mg/l Mean cell residence time = 10 d Return sludge from SST = 8000 mg/l Yield coefficient = 0.8 kg/kg Endogenous decay rate constant = 0.06 d-¹ Determine: Question i. The volume of aeration tank ii. The mass and volume of sludge to be wasted per day iii. The recycle ratio iv. Food to microorganism ratio

Structural Analysis

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Chapter2: Loads On Structures

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The storm drains system transports rainwater or stormwater and other runoff from roads, parking lots, and roof downpipes directly to nearby creeks, rivers, or the sea without any treatment.

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Q1: A conventional ASP is to be used for treatment of 10,000 m³/d of municipal
wastewater. The influent BOD to the ASP is 160 mg/l. As per requirements, the
effluent from the ASP should have a soluble BOD of not more than 10 mg/l.
Assuming:
i.
The volume of aeration tank
ii. The mass and volume of sludge to be wasted per day
iii.
The recycle ratio
iv. Food to microorganism ratio
Notes-
a
Comment
Y
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A TextBox Arrange -
4
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26°C Light rain
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1. A natural water with a flow of 4.0 MGD is to be treated with a commercial-grade alum dosage of 80 mg/l. Determine the amount of alum required (expressed in lbs/day), the amount of natural alkalinity required to complete the reaction (expressed in mg/l as CaCO3 and kg/day), and the amount of Al(OH)3(s) sludge produced (expressed in lbs/day and gal/day) if the sludge contains 2.2% solids by weight and the S.G. of the dry solids is 2.0.
Hi Please try to solve Last time you solved this problem but result is incorrect.
A bio-tower composed of a modular plastic medium of 6 m is used as secondary treatment component in a municipal wastewater treatment plant. Flow from the primary clarifier is 25000 m³/day with 200 mg/1 BOD. The treatability constant is 0.06 per min. To produce an effluent with a soluble BOD of 20 mg/1, the surface area as per Eckenfelder (coefficient related to medium is 0.5) is approximately:
2a
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A complete-mixed activated sludge process is to be designed to treat 5.0 MGD of primary effluent having a BOD5 of 180 mg/L. The requirement is that the effluent BOD5 and TSS concentration be 20 mg/L or less on an annual average basis. The following biokinetic coefficient obtained at 15°C: Y = 0.6 mg VSS/mg BOD5, k=2.85d-¹, Ks = 70 mg/L BOD5, and kå = 0.041 d¹¹. Assume that the MLVSS concentration in the aeration basin is maintained at 2,500 mg/L. Determine: a. The minimum MCRT (d) b. The MCRT necessary to meet the requirement (d) C. The volume of the aeration basin (ft³)
Biomass and substrate mass balance equations can be merged giving QwXR/VX=Y/X (Qo/V) (So-S)-kd (i) Prove that X= SRT/HRT Note that HRT = t and SRT = tc. (ii) If you are an engineer working in a wastewater consultancy company, and obtained the following data: - SRT = 20 days HRT 20 hours = (Y(So-S)/1+kd(SRT)). So = 350 mg/L S = 100 mg/L Y = 0.15 kd = 0.22 per day Calculate the increment of MLSS (%) required in the aerobic tank if the discharge BOD5 in the effluent needs to achieve 10 mg/L.
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