Discussion Using the same relation with h₂ 0 gives t 43.1 min for the discharge of the entire amount of water in the tank. Therefore, emptying the bottom half of the tank takes much longer than emptying the top half. This is due to the decrease in the average discharge velocity of water with decreasing h.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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Kindly solve the color red underlined and boxed given. Provide a complete solution of h2 = 0 gives t= 43.1 min

A 4-ft-high, 3-ft-diameter cylindrical water tank whose top is open to the
atmosphere is initially filled with water. Now the discharge plug near the
bottom of the tank is pulled out, and a water jet whose diameter is 0.5 in
streams out (Fig. 5-13). The average velocity of the jet is approximated as
V = V2gh, where h is the height of water in the tank measured from the
center of the hole (a variable) and g is the gravitational acceleration. Deter-
mine how long it takes for the water level in the tank to drop to 2 ft from
the bottom.
Analysis We take the volume occupied by water as the control volume. The
size of the control volume decreases in this case as the water level drops,
and thus this is a variable control volume. (We could also treat this as a
fixed control volume that consists of the interior volume of the tank by dis-
regarding the air that replaces the space vacated by the water.) This is obvi-
ously an unsteady-flow problem since the properties (such as the amount of
mass) within the control volume change with time.
The conservation of mass relation for a control volume undergoing any pro-
cess is given in rate form as
mout
dmev
dt
(1)
h+
0
ho
h₂
Air
Water
tank
Dja
Transcribed Image Text:A 4-ft-high, 3-ft-diameter cylindrical water tank whose top is open to the atmosphere is initially filled with water. Now the discharge plug near the bottom of the tank is pulled out, and a water jet whose diameter is 0.5 in streams out (Fig. 5-13). The average velocity of the jet is approximated as V = V2gh, where h is the height of water in the tank measured from the center of the hole (a variable) and g is the gravitational acceleration. Deter- mine how long it takes for the water level in the tank to drop to 2 ft from the bottom. Analysis We take the volume occupied by water as the control volume. The size of the control volume decreases in this case as the water level drops, and thus this is a variable control volume. (We could also treat this as a fixed control volume that consists of the interior volume of the tank by dis- regarding the air that replaces the space vacated by the water.) This is obvi- ously an unsteady-flow problem since the properties (such as the amount of mass) within the control volume change with time. The conservation of mass relation for a control volume undergoing any pro- cess is given in rate form as mout dmev dt (1) h+ 0 ho h₂ Air Water tank Dja
Integrating from t = 0 at which h = ho to t = t at which h = h₂ gives
Dank
dh
Vho
Vh₂
Dit V2g
Vg/2
Substituting, the time of discharge is determined to be
Cat
dt =
<->1=
t=
Dank
D.
V4 ft- V2 ft (3 x 12 in)
V32.2/2 ft/s²
0.5 in
Therefore, it takes 12.6 min after the discharge hole is unplugged for half of
the tank to be emptied.
= 757 s = 12.6 min
Discussion Using the same relation with h₂ = 0 gives t = 43.1/min for h
the discharge of the entire amount of water in the tank. Therefore, emptying
the bottom half of the tank takes much longer than emptying the top half.
This is due to the decrease in the average discharge velocity of water with
decreasing h.
0
ho
h₂
Air
Water
Dunk
|Djat
Transcribed Image Text:Integrating from t = 0 at which h = ho to t = t at which h = h₂ gives Dank dh Vho Vh₂ Dit V2g Vg/2 Substituting, the time of discharge is determined to be Cat dt = <->1= t= Dank D. V4 ft- V2 ft (3 x 12 in) V32.2/2 ft/s² 0.5 in Therefore, it takes 12.6 min after the discharge hole is unplugged for half of the tank to be emptied. = 757 s = 12.6 min Discussion Using the same relation with h₂ = 0 gives t = 43.1/min for h the discharge of the entire amount of water in the tank. Therefore, emptying the bottom half of the tank takes much longer than emptying the top half. This is due to the decrease in the average discharge velocity of water with decreasing h. 0 ho h₂ Air Water Dunk |Djat
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