Discuss the continuity of the function on the closed interval. g(x)=√√8-x³, [-2, 2] O The function is continuous on [-2, 2] because 8-x³ <0 on [-2, 2]. O The function is continuous on [-2, 2] because 8 - x³20 on [-2, 2]. O The function is not continuous on [-2, 2] because g(-2) is not defined. O The function is not continuous on [-2, 2] because g(0) is not defined. O The function is not continuous on [-2, 2] because g(2) is not defined. Show My Work (Required)? What steps or reasoning did you use? Your work counts towards your score. You can submit show my work an unlimited number of times. Show My Work has not been graded yet. I

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