Discuss the continuity of the function on the closed interval. g(x)=√√8-x³, [-2, 2] O The function is continuous on [-2, 2] because 8-x³ <0 on [-2, 2]. O The function is continuous on [-2, 2] because 8 - x³20 on [-2, 2]. O The function is not continuous on [-2, 2] because g(-2) is not defined. O The function is not continuous on [-2, 2] because g(0) is not defined. O The function is not continuous on [-2, 2] because g(2) is not defined. Show My Work (Required)? What steps or reasoning did you use? Your work counts towards your score. You can submit show my work an unlimited number of times. Show My Work has not been graded yet. I
Discuss the continuity of the function on the closed interval. g(x)=√√8-x³, [-2, 2] O The function is continuous on [-2, 2] because 8-x³ <0 on [-2, 2]. O The function is continuous on [-2, 2] because 8 - x³20 on [-2, 2]. O The function is not continuous on [-2, 2] because g(-2) is not defined. O The function is not continuous on [-2, 2] because g(0) is not defined. O The function is not continuous on [-2, 2] because g(2) is not defined. Show My Work (Required)? What steps or reasoning did you use? Your work counts towards your score. You can submit show my work an unlimited number of times. Show My Work has not been graded yet. I
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Discuss the continuity of the function on the closed interval.
g(x)=√√8-x3, [-2, 2]
O The function is continuous on [-2, 2] because 8 - x³ <0 on [-2, 2].
O The function is continuous on [-2, 2] because 8x³20 on [-2, 2].
O The function is not continuous on [-2, 2] because g(-2) is not defined.
O The function is not continuous on [-2, 2] because g(0) is not defined.
O The function is not continuous on [-2, 2] because g(2) is not defined.
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Transcribed Image Text:Discuss the continuity of the function on the closed interval.
g(x)=√√8-x3, [-2, 2]
O The function is continuous on [-2, 2] because 8 - x³ <0 on [-2, 2].
O The function is continuous on [-2, 2] because 8x³20 on [-2, 2].
O The function is not continuous on [-2, 2] because g(-2) is not defined.
O The function is not continuous on [-2, 2] because g(0) is not defined.
O The function is not continuous on [-2, 2] because g(2) is not defined.
74°F
Sunny
Show My Work (Required)?
What steps or reasoning did you use? Your work counts towards your score.
You can submit show my work an unlimited number of times.
Show My Work has not been graded yet.
H
Q
▬
a
I
B
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