Discrete Probability Distributions: 8. Suppose that two 6-sided dice are rolled. Let a random variable take on the value of an even sum. Hint: this will be a conditional distribution. a.) Find the probability distribution. b.) Find the mean of the probability distribution. c.) Find the variance and the standard deviation of the probability distribution.

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8. Suppose that two 6-sided dice are rolled. Let a random variable take on the value of an even sum. Hink this will be a conditional distribution. a.) Find the probability distribution. b.) Find the mean of the probability distribution. c.) Find the variance and the standard deviation of the probability distribution.
Discrete Probability Distributions:
8. Suppose that two 6-sided dice are rolled. Let a random variable take on the value of an even sum. Hint: this
will be a conditional distribution.
a.) Find the probability distribution.
b.) Find the mean of the probability distribution.
c.) Find the variance and the standard deviation of the probability distribution.
Transcribed Image Text:Discrete Probability Distributions: 8. Suppose that two 6-sided dice are rolled. Let a random variable take on the value of an even sum. Hint: this will be a conditional distribution. a.) Find the probability distribution. b.) Find the mean of the probability distribution. c.) Find the variance and the standard deviation of the probability distribution.
Expert Solution
Step 1: part a>

To solve this problem, we first need to list all the possible outcomes when rolling two 6-sided dice. Each die has 6 faces, so there are 6 cross times 6 equals 36 total outcomes.

The outcomes with an even sum (2, 4, 6, 8, 10, or 12) can occur in the following ways:

  • 1 way to get a sum of 2: (1, 1)
  • 3 ways to get a sum of 4: (1, 3), (2, 2), (3, 1)
  • 5 ways to get a sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)
  • 5 ways to get a sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2)
  • 3 ways to get a sum of 10: (4, 6), (5, 5), (6, 4)
  • 1 way to get a sum of 12: (6, 6)

Now, let's calculate the probabilities for each of these outcomes:

a.) Probability Distribution:

  • P(sum = 2) = 1/36
  • P(sum = 4) = 3/36 = 1/12
  • P(sum = 6) = 5/36
  • P(sum = 8) = 5/36
  • P(sum = 10) = 3/36 = 1/12
  • P(sum = 12) = 1/36
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