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- Direction: Read and understand the ff. set of monohybrid cross problems and answer each problem by showing the Punnett square, genotypes ans phenotypes. 3. In tomatoes, red fruit (R) is dominant over yellow fruit (r). A plant that is homozygous for red fruit is crossed with a plant that has yellow fruit. What would be the genotypes and phenotypes? 4. If two of the first generation offspring from the problem above were mated, what would be the genotypes and phenotypes of the second generation?Direction: Read and understand the ff. set of monohybrid cross problems and answer each problem by showing the Punnett square, genotypes and phenotypes. 5. In humans, being a tongue roller (R) who is a non-roller marries a woman who is heterozygous for tongue rolling. dominant over non-roller (r). A man a. Father's phenotype: b. Father's genotype: c. Mother's phenotype: d. Mother's genotype:Direction: Read and understand the ff. set of monohybrid cross problems and answer each problem by showing the Punnett square, genotypes ans phenotypes. 2. Horniess (H) in cattle is dominant over horned (h). A homozygous hornless bull is mated with a homozygous horned cow. What will be the genotype and phenotype of the first generation?
- Direction: Answer the following problems: 1. Predict the phenotypic ratios of offspring when a homozygous white cow is crossed with a roan bull. Illustrate using a Punnett square. 2. Complete the Punnett square for a cross between a black chicken (BB) and a white chicken (WW). Give the phenotype of the offspring in the F1 generation. Кey BB – black ww- white F1 BW – checkered Phenotype:а. a chart that shows the combinations (results) for a cross 8. Genetics b. a picture (diagram) that shows genetics pass from generation (pass from 9. Alleles parents to kids to 10. Punnett grandkids) Square genotype of 2 DIFFERENT alleles (Bb, Dd, Aa...) с. 11. Phenotype d. the information on the alleles / Genes (ex. TT, Tt, tt) 12. Genotype e. a person's Physical appearance; their characteristics (ex. Brown eyes) 13. Homozygous f. a type of gene - we get one from our mom and one from our dad. 14. Heterozygous g. genotype of two of the SAME alleles (AA, aa, BB, bb...) 15. Pedigree h. the study of heredity and the variations of characteristics (how people look differently)NAME: Patterns of Inheritance Worksheet 1. True Breeding Parental Cross A homozygous dominant purple flowered plant is crossed with a homozygous recessive white flowered plant. a. What are the genotypes of the parent plants? (Use the Punnett square to determine the outcomes of this cross. Remember to place the gametes along the left side and top of the square. (P=Purple, p=white) b. What is the genotype of all F₁ plants? 1 b. c. What is the phenotype of all F₁ plants? C. d. How many plants out of 4 will produce white flowers? d. a. 2. Monohybrid Cross: The F₁ offspring from the above problem are allowed to self fertilize. a. What are the genotypes of the F₁ parents? a. (Use the Punnett square to determine the outcomes of this cross. Remember to place the gametes along the left side and top of the square.) b. What is the genotype ratio for this cross? c. What is the phenotype ratio for this cross? d. How many plants out of 4 will produces white flowers? d. b. C.
- Show Comments Track Changet O Markup OptionS Track Changes wious Next Genetics Lab Exercise (by Dr. Lapik) Question 2. 田 BB = black Analyze the following dihybrid cross: Bb = black Parents: bbLI bb = white LL = short hair U = short hair Gametes: U= long hair Punnett Square: How many of the offspring are: Black, Short Black, Long White, Short White, Long Autupay Credentials Username ENNIN Citrix1. Study the given alleles. Write the correct phenotype for each genotype. X – normal Gen otype xC - Color-blind Phenotype XX XY XXC xCY 2. Study the given alleles. Write the correct genotype for each phenotype. xH - Hemophiliac Phenotype X- normal Gen otype Hemophiliac female Hemophiliac male Normal female carrier of the gene Normal male Normal female 28 3. Determine the genotype and phenotype of the offspring. A color-blind mother (XCx) married a normal sighted (XY) father. Genotype: Phenotype: Genotype: Phenotype: Genotype: Genotype: Phenotype: Phenotype: a. There are b. There are c. There are d. There are % normal sons. % normal daughters. % color-blind sons. % color-blind daughters. % normal female, carrier of the disorder. or or or or e. There are ort 2. ng. Questions and Problems Given the pedigree below, answer the following questions separately for each pedigree. 1. What is the mode of inheritance? 2 Write the genotype of the individuals in the pedigree based on the mode of inheritance given. date distance Pedigree 1 gous Pedigree 2 Recombination zzel 9rd To ya hisiga of elds ed bittorie 10 Tube heterozygpitanjonosenis the fasiria cell while the tester, taken as the raingoz, mix on the allele of the nie of Deteraniol are now adva Hol Tidmoos DNG sevel. This cross will produce filial generation (2) walthen purple ves f 11020 12 13 encont 000 sg nomi 2 is importan gies to do this, scientists preously 4 méte based monso nomiskt sild devon S01 000 05 1uodo 910 919/3 2m al m 29098 3291T 20 comondo of pes. The value is, the OTO the value is the closer 1 2 nesten che 3 4 5 6 I snag- niboo to 19dmun srid wordt oo Jadigrappen va bo trog do disp ambe 000 61 251110010 aliso ist was by The song Shear Besa STS GRAD color. In his experimenti…
- A. Identify the genotypes of the male and female used in cross 2. B. Identify the cross in which the female parent was most likely heterozygous. C. Explain how the results exclude the possibility that the trait is encoded by a mitochondrial gene.Answer the following. Letters only. 1. In mice, black color (B) is dominant over brown (b), and a solid pattern (S) is dominant over white spotted (s). Color and spotting are controlled by genes that assort independently. A homozygous black, spotted mouse is crossed with a homozygous brown, solid mouse. All the F1 mice are black and solid. What are the genotypes of the parents? * a. BBSs and bbss b. BBSs and bbSS c. BbSs and bbSs d. BBss and bbss e. BBss and bbSS f. None of the choices 2. In mice, black color (B) is dominant over brown (b), and a solid pattern (S) is dominant over white spotted (s). Color and spotting are controlled by genes that assort independently. A homozygous black, spotted mouse is crossed with a homozygous brown, solid mouse. All the F1 mice are black and solid. What will be the genotypic probability of the first filial (F1) generation offspring? * a. 100% BBSS b. 100% BbSs c. 50% BBSS and 50% BbSs d. 25% BBSS; 50% BbSs and 25% bbss e. 100% black, solid mice…Answer the following questions. 1. Construct a map for the genes d,e,f. Assume that: d and e = 3%; e and f = 5%. Give 2 arrangements of the genes/maps. 2. If d and f = 2%, what is the correct arrangement of the genes d,e,f? 3. Consider the fourth gene "g". if g and e = 1.5%, give two possible arrangements. 4. If d and g = 1.5 % give the correct order of the four genes %3D