Answered: Direction of propagation A |C

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Question

Expert Solution

Step 1

(a) Average intensity of EM wave is given by,

$I_{a v g} = \frac{c ε_{0} E_{m a x}^{2}}{2}$

At point A, intenisty is maximum, then rearranging above equation

$\Rightarrow E_{m a x}^{2} = \frac{2 I_{a v g}}{c ε_{0}}$ ---------Eqn(1)

where,

$c - S p e e d o f l i g h t (c = 3 \times 10^{8} m / s) ε_{0} - P e r m i t t i v i t y o f f r e e s p a c e (ε_{0} = 8.85 \times 10^{- 12} C / N m^{2})$

Given that, $I_{a v g} = 13.275 \times 10^{- 12} W / m^{2}$

substituting the values in Eqn(1)

$\Rightarrow E_{m a x}^{2} = \frac{(2 \times 13.275 \times 10^{- 12} W / m^{2})}{(3 \times 10^{8} m / s \times 8.85 \times 10^{- 12} C / N m^{2})} \Rightarrow E_{m a x}^{2} = 1 \times 10^{- 8} N^{2} / C^{2} \Rightarrow E_{m a x} = \sqrt{(1 \times 10^{- 8} N^{2} / C^{2})} \Rightarrow E_{m a x} = 1 \times 10^{- 4} N / C$