Differentiate. f'(x) = f(x) = 8x7-9 cos(x)

Q: Find the 7th derivative of: f(x)=sin(x)cos(x) f’=? • • •

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Q: f'(x) = Let f(x)= = I cos ³

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Q: f(x) = -2x cos(x)

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Q: f(x)=(6+x^3)^cos x Explain with steps

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Q: Determine f '(x) for function f(x)= x2 tan x

A: Firstly, we use product rule of differentiation, which is (uv)'=uv'+u'v as shown on board.

Q: Let f'(x) = f'( 5 ) = f(x) = 3 sin x + 12 cos x

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Q: / If f(x) = 2x (Sinx+cosx) find. f'(x) = ' (5) =

A: Given function  f( x ) = 2x( sinx + cosx )

Q: Differentiate f (x) = cos (In x) e“.

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Q: Find f. f ''(?) = sin(?) + cos(?),    f(0) = 5,    f '(0) = 2 f(?) =

A: Given that        f"( θ) = sin(θ)+cos(θ)  The initial condition is f(0)=5 and f'(0)=2 We have to…

Q: f(x)=x+sinx / x2+cosx f '(x)=?

A: Given function: Now,

Q: Find f''(x) if f(x)=ex cos(x)+x3

A: Find f''(x) if f(x)=ex cos(x)+x3

Q: Find f'(0) if f (x) = In(cos .x).

A: we have to find f'(0)

Q: et f(x)=-11sin x+3 cos x f' (x)=?

A: f(x)=-11sin x+3 cos x this is given  we have to differentiate the function  dsinx/dx = cosx…

Q: FIND F'(x) F(x) = 2 tanx 1+cosx

A: To differentiate the given function.

Q: Find f. f ''(?) = sin ? + cos ?,    f(0) = 1,    f '(0) = 3

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Q: Differentiate while showing the necessary steps. y=f(x)=x^2(cos⁡(x))

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Q: x sin x f(x) = = -9e | f'(x) =

A: Use product and chain rule of derivative

Q: Let f(x)=(6sinx+2cosx)tan−1x f'(x) =

A: Consider the function

Q: find where f'(c)=0 f(x)=-cos4x

A: Given, function