Differentiate: g(x)= (2x³ – 1)(x³ + 2) g'(x) = 10x* (2r³ – 1) + 3r²(r³ + 2) g'(x) = 10x“(2³ + 2) – 3z²(2r" – 1) g'(x) = 3x²(2r³ – 1) + 10z*(x³ + 2) %3D gʻ(x) = (3x²)(10x“) %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Differentiate: g(x) = (2x5 – 1)(x3 + 2)
...
g'(x) = 10x* (2x³ – 1) + 3r² (x³ + 2)
A
g' (x) = 10x*(x³ +2) – 32²(2x³ – 1)
(в
-
g'(x) = 3x²(2x³ – 1) + 10x*(x³ + 2)
g (x) = (3x²)(10x4)
Transcribed Image Text:Differentiate: g(x) = (2x5 – 1)(x3 + 2) ... g'(x) = 10x* (2x³ – 1) + 3r² (x³ + 2) A g' (x) = 10x*(x³ +2) – 32²(2x³ – 1) (в - g'(x) = 3x²(2x³ – 1) + 10x*(x³ + 2) g (x) = (3x²)(10x4)
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