Diethyl Zinc is a very unstable compound. When it comes in contact with the air, it burns to form zinc oxide, CO2, and water. The reaction occurs as the Diethyl Zinc comes into contact with oxygen molecules. The chemical equation is as follows: Zn(C2HS)2 (1) + 502 (g) → ZnO(s) + 4CO2(g) + 5H20(1) a) Given the following data calculate the entropy change for this reaction. All data is at 298 K. Zn(C2HS)2 (1), Sm° = 290.2 J K' mol1 O2 (8), Sm° = 205.138 J K' mol1 ZnO(s), Sm° = 43.64 J K1 mol1 CO2(8), Sm° = 213.74 J K' mol1 H20(1), Sm° = 69.91JK' mol1 b) The reaction is known to be highly exothermic. Comment on whether the reaction is spontaneous or not.

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Diethyl Zinc is a very unstable compound. When it comes in contact with the air, it burns
to form zinc oxide, cO2, and water. The reaction occurs as the Diethyl Zinc comes into
contact with oxygen molecules. The chemical equation is as follows:
Zn(C2HS)2 (1) + 502 (g) → Zno(s) + 4CO2(g) + 5H20(1)
a) Given the following data calculate the entropy change for this reaction. All data is at
298 K.
Zn(C2HS)2 (1), Smº = 290.2 J K' mol1
O2 (g), Sm° = 205.138 J K' mol1
Zno(s), Sm° = 43.64 J K' mol1
CO2(g), Sm° = 213.74 J K' mol1
H20(I), Sm° = 69.91 J K' mol1
%3!
b) The reaction is known to be highly exothermic. Comment on whether the reaction is
spontaneous or not.
Transcribed Image Text:Diethyl Zinc is a very unstable compound. When it comes in contact with the air, it burns to form zinc oxide, cO2, and water. The reaction occurs as the Diethyl Zinc comes into contact with oxygen molecules. The chemical equation is as follows: Zn(C2HS)2 (1) + 502 (g) → Zno(s) + 4CO2(g) + 5H20(1) a) Given the following data calculate the entropy change for this reaction. All data is at 298 K. Zn(C2HS)2 (1), Smº = 290.2 J K' mol1 O2 (g), Sm° = 205.138 J K' mol1 Zno(s), Sm° = 43.64 J K' mol1 CO2(g), Sm° = 213.74 J K' mol1 H20(I), Sm° = 69.91 J K' mol1 %3! b) The reaction is known to be highly exothermic. Comment on whether the reaction is spontaneous or not.
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